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Ede4ka [16]
2 years ago
8

Jim works mowing lawns and babysitting. He earns $8.80 an hour for mowing and $8.10 an hour for babysitting. How much will he ea

rn for 1 hour of mowing and 5 hours of babysitting?
Mathematics
2 answers:
kicyunya [14]2 years ago
8 0

Answer: $8.80 for one hour of mowing and $40.50 for 5 hours of babysitting

Step-by-step explanation:

Paladinen [302]2 years ago
5 0

Answer:

Jim would earn $49.30

Step-by-step explanation:

For babysitting, multiply 5 (hours) by 8.10 which will get you 40.5

Add 40.5 to 8.80 since he only does 1 hour of mowing, and you get $49.30

Hope this helps!!

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True or false, 4x-3+x+7 would equal 5x-10​
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Answer:

false

Step-by-step explanation:

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Maria has gotten scores of 75, 77, 81 and 84 (out of a possible 100) on the four midterm examinations for a math class. If each
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Answer:

93.63

Therefore, she need to get a minimum of 93.63 out of 100 in the final exam

Step-by-step explanation:

Given;

Each midterm exam = 15% of total grade

Final exam = 40% of total grade

Midterm scores = 75, 77, 81 and 84 (out of a possible 100)

Total midterm score = 75+77+81+84 = 317

To determine the grade of the four midterm exams in the total score;

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= 0.15×317

= 47.55 %

To get a minimum score of 85 % of the total score, the amount of the total score to be secured in the final exam is;

Final exam = 85% - 47.55% = 37.45%

Since final exam is 40% of the total score;

It means she need to get 37.45% out of 40% of the final exam.

Converting it to a score of 100;

Final exam score = 37.45/40 × 100

Final exam score = 93.63

Therefore, she need to get a minimum of 93.63 out of 100 in the final exam

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2 years ago
IQ scores for adults aged 20 to 34 years are normally distributed according to N (110,25). Use the empirical rule to answer the
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Since the mean of the distribution is 110, and the distribution is normal, then 50% of the the people will have scores below 110.
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Solve the proportion 5/12=y/15
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Calculate s f(x, y, z) ds for the given surface and function. g(r, θ) = (r cos θ, r sin θ, θ), 0 ≤ r ≤ 4, 0 ≤ θ ≤ 2π; f(x, y, z)
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\mathrm dS=\|g_r\times g_\theta\|\,\mathrm dr\,\mathrm d\theta=\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta

and the integral is

\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\int_0^{2\pi}\int_0^4((r\cos\theta)^2+(r\sin\theta)^2)\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta

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###

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r=\sinh s\implies\mathrm dr=\cosh s\,\mathrm ds

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\displaystyle=\int_0^{\sinh^{-1}4}\cosh^4s\,\mathrm ds

=\displaystyle\frac18\int_0^{\sinh^{-1}4}(3+4\cosh2s+\cosh4s)\,\mathrm ds

and the result above follows.

4 0
3 years ago
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