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3 years ago

7

Help meee!!!!!!!! I need this to graduate!!!!!!!

2 answers:

kifflom [539]3 years ago

5 0

All cubic functions that are centered upon the x axis have a slope of 0 when x = 0

Pie3 years ago

3 0

Answer:

• Slope is the derivative of the function:

${ \rm{f(x) = {x}^{3} + 3 {x}^{2} + 3x + 1 }} \\ \\ { \tt{ \frac{dy}{dx} = 3 {x}^{2} + 6x + 3 + 0 }}$

• At, x = 0

${ \tt{ \frac{dy}{dx} = 3 {(0)}^{2} + 6(0) + 3}} \\ \\ { \boxed{ \tt{slope = 3}}}$

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Write an equation of the line perpendicular to the given line that contains P.

snow_tiger [21]

Step-by-step explanation:

As the required line is perpendicular to y = (1/2)x + 5, product of slope of y = (1/2)x + 5 and required line should be - 1.

=> (1/2)m = - 1

=> m = - 2

Thus, required line is

=> y - (-8) = (-2)(x - 3)

=> y + 8 = -2(x - 3)

5 0

3 years ago

13. f(x) = -x + 4x^3 -2

Oksi-84 [34.3K]

Answer:

x = 5

Step-by-step explanation:

7 0

3 years ago

a lunch stand makes a $.75 profit on each chef's salad and $1.20 profit on each caesar salad. On a typical weekday, it sells bet

tangare [24]

Answer:

<em>50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.</em>

Step-by-step explanation:

Suppose, the number of Chef's salad is $x$ and the number of Caesar salad is $y$

On a typical weekday, it sells between 40 and 60 Chefs salads and between 35 and 50 Caesar salads.

So, the two constraints are: $40\leq x\leq 60$ and $35\leq y\leq 50$

The total number sold has never exceed 100 salads. So, another constraint will be: $x+y\leq 100$

According to the graph of the constraints, the vertices of the common shaded region are: $(40,35), (60,35), (60,40), (50,50)$ and $(40,50)$ <em>(Refer to the attached image for the graph)</em>

The lunch stand makes a $.75 profit on each Chef's salad and $1.20 profit on each Caesar salad. So, the profit function will be: $P=0.75x+1.20y$

For (40, 35) , $P=0.75(40)+1.20(35)=72$

For (60, 35) , $P=0.75(60)+1.20(35)=87$

For (60, 40) , $P=0.75(60)+1.20(40)=93$

For (50, 50) , $P=0.75(50)+1.20(50)=97.5$ <u><em>(Maximum)</em></u>

For (40, 50) , $P=0.75(40)+1.20(50)=90$

Profit will be maximum when $x=50$ and $y=50$

Thus, 50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.

6 0

4 years ago

How would I graph this?

elena55 [62]

$y\leq 2x-5$

↝ x-intercept

$2x-5=0\\2x=5\\x=\frac{5}{2}$

↝ y-intercept

y = -5

↝ $y\leq 2x-5$ means that the shade/area is below the graph as shown in the first picture.

$y\leq -\frac{1}{2}x-3$

↝ x-intercept

$-\frac{1}{2}x-3=0\\-x-6=0\\-x=6\\x=-6$

↝ y-intercept

y = -3

↝ Since it's "≤" therefore. The shade/area is below the graph. For second picture.

First picture is first inequality

Second picture is second inequality.

3 0

3 years ago

At Hoffman's Bike Rentals, it costs $33 to rent a bike for 8 hours. How many hours of bike use does a customer get per dollar?

viktelen [127]

0.24 repeating so rounding it to the nearest hundredth would make it stay 0.24<span />

5 0

3 years ago