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laila [671]
3 years ago
13

Mario needs 1024 MB to make a backup of his computer files, for this he has 3 USB memories with a capacity of 256 MB. How many U

SB sticks with a 128 MB capacity does Mario need for this task?
Mathematics
2 answers:
Brut [27]3 years ago
6 0
256 x 3 is uhh 768 so it would be 2 of the 128 sticks
grigory [225]3 years ago
4 0
………. i don’t even know if that makes sense….
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What two numbers multiplied together equal 900, but also added together equal -68?
vlabodo [156]
-50 and -18 multiplied together equal 900 and added together equal -68 because a - times a- equals a positive.
3 0
4 years ago
At which root does the graph of f(x) = (x+4)6(x + 7)5 cross the x axis?
Licemer1 [7]

Answer:

x = -7

Step-by-step explanation:

Our function is f(x) =(x+4)^6(x+7)^5. Notice that our possible roots are when x + 4 = 0 and when x + 7 = 0. So, our roots are -4 and -7.

However, the power above x + 4 is even, meaning the graph will simply <em>touch</em> the x-axis at x = -4, but not pass through. The power above x + 7, though, is odd, which means the graph will <em>cross</em> the x-axis.

Thus, the answer is x = -7.

5 0
3 years ago
Read 2 more answers
Explain whether the product of an even number x odd number x odd number is even or odd?
Dmitriy789 [7]
Well an example is 4x3x3 which equals 36 which is even
3 0
4 years ago
Read 2 more answers
Answer step by step
enot [183]
Consider, please, this solution/explanation:
1. suppose, that number of cars is 'x', numbers of buses is 'y'.
2. according to the condition 'a total of 32', it means that x+y=32. This is the 1st equation.
3. according to the condition in one car are 3x persons, in one bus are 27y persons, and totaly 3x+27y=408 people. This is the 2d equation.
4. if to solve the system of two equations:
\left \{ {{x+y=32} \atop {3x+27y=408}} \right. \ =\ \textgreater \  \  \left \{ {{x=19 (cars)} \atop {y=13(buses)}} \right.

Answer: 13 - b., 19 - c.
6 0
3 years ago
What is the binomial expansion of (2x – 3)^5?
Tanya [424]

Answer:

C

Step-by-step explanation:

(2x + 3)^5 = C(5,0)2x^5*3^0 +

C(5,1)2x^4*3^1 + C(5,2)2x^3*3^2 + C(5,3)2x^2*3^3 + C(5,4)2x^1*3^4 + C(5,5)2x^0*3^5

Recall that

C(n,r) = n! / (n-r)! r!

C(5,0) = 1

C(5,1) = 5

C(5,2) = 10

C(5,3) = 10

C(5,4) = 5

C(5,5) = 1

= 1(2x^5)1 + 5(2x^4)3 + 10(2x^3)3^2 + 10(2x^2)3^3 + 5(2x^1)3^4 + 1(2x^0)3^5

= 2x^5 + 15(2x^4) + 90(2x^3) + 270(2x^2) + 405(2x) +243

= 32x^5 + 15(16x^4) + 90(8x^3) + 270(4x^2) + 810x + 243

= 32x^5 + 240x^4 + 720x^3 + 1080x^2 + 810x + 243

7 0
3 years ago
Read 2 more answers
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