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Stolb23 [73]
2 years ago
15

My sis is having a hard time simplifying a problem. I'm not good at simplifying myself So I cant help her ):P

Mathematics
1 answer:
stich3 [128]2 years ago
7 0

3 x 2 x 2 x 2 x 2 / 2 x 2 x 2

48 / 2 x 4

[48 can be simplified to 24 x 2 and 4 can be simplified to 2 x 2]

24 x 2 / 2 x 2 x 2

[24 can be simplified to 12 x 2]

12 x 2 x 2 / 2 x 2 x 2

[12 can be simplified to 6 x 2]

6 x 2 x 2 x 2 / 2 x 2 x 2

[6 can be simplified to 3 x 2]

3 x 2 x 2 x 2 x 2 / 2 x 2 x 2

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Log 15 (2x − 2) = log 15 (x+9)
notka56 [123]

Answer:

x=11

Step-by-step explanation:

Given the equation

\log_{15}(2x-2)=\log_{15}(x+9)

Note that

2x-2>0\\ \\2x>2\\ \\x>1

and

x+9>0\\ \\x>-9

Combined, x>1

Solve the equation:

2x-2= x+9\\ \\2x-x=9+2\\ \\x=11

Since 11>1, this is the solution to the equation.

5 0
3 years ago
Two angles are complementary. The measure of one angle is 3° more than one-half of the measure of the other. Find the measure of
vagabundo [1.1K]

Answer:

doge

Step-by-step explanation:

EAnswers avatar

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8 0
2 years ago
How much will it cost for the family of four
antiseptic1488 [7]
Do you have the rest of the question?
6 0
3 years ago
Fill in the missing numbers in these equation <br> (-2) . (-4.5)= ? <br> ?=
Nina [5.8K]
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Multiplying two negatives makes it positive.
5 0
2 years ago
HELPP!!what is the answer to this picture above^
nasty-shy [4]

Answer:

\fbox{ \fbox { \sf{Distance  =  \sf{15 \: units}}}}

{ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}

Step-by-step explanation:

\star{ \:  \sf { \: Let \: the \: points \: be \: A \: and \: B}}

\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}

\underline{ \underline{ \tt{Finding \: the \: distance}}}

\boxed{ \sf{Distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(18 - 6)}^{2}  +  {(15 - 6)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(12)}^{2}  +  {(9)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{144 + 81}}}

\mapsto{ \sf{Distance =  \sqrt{225} }}

\mapsto{ \sf{Distance =  \sqrt{ {15}^{2} } }}

\mapsto{  \boxed{\sf{Distance = 15 \: units}}}

\underline{ \underline {\tt{Finding \: the \: Midpoint}}}

\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2}  \: , \:  \frac{y1 + y2}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2}  \: , \:  \frac{6 + 15}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{24}{2}  \: , \:  \frac{21}{2} )}}

\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

3 0
3 years ago
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