Answer:
<h2>D. 18</h2>
Step-by-step explanation:
We know:
1. Diagonals of a rhombus are perpendicular.
2. Diagonals divide the rhombus on four congruent right triangles.
3. The sum of measures of acute angles in a right triangle is equal 90°.
Angles CAD and ACB are alternate angles. Therefore they are congruent:
m∠DAC = m∠ACB ⇒ m∠ACB = x°.
From 3. we have the equation:
(5x - 18) + x = 90
(5x + x) - 18 = 90 <em>add 18 to both sides</em>
6x = 108 <em>divide both sides by 6</em>
x = 18
Answer:
Your answer should be (B.) Both calculated the slope as 1 over 3
Step-by-step explanation:
First of all, it has to be A or B. The question does say that they have to calculate it accurately. You can't do that if they are both different. Second, remember rise over run. The rise of the first triangle is 2, and the run is 6. Simplify that to get 1/3. Now, we can stop there because B is the only possible answer.
Hope I helped! =)
Answer:
The answer to this question is simply NO. There is exactly one line through any two points and exactly one plane through any three points not on the same line. Therefore, any two points on the prism must be collinear and coplanar.
...
Step-by-step explanation:
We have been asked that:
is it possible for two points collinear nor coplanar?
<u>Collinear points:</u>
Collinear points are points that lie on the same line.
<u>Coplanar points:</u>
Coplanar points are points that lie on the same plane.
The answer to this question is simply NO. There is exactly one line through any two points and exactly one plane through any three points not on the same line. Therefore, any two points on the prism must be collinear and coplanar.
...
Well according to the slope intercept equation.
Y = mx +/- b
The slope is the value m
The y intercept is b
To graph the function, one sure way to do it is simply make a table of values picking any x values that fall within the graph space, and finding out the resulting y values and using the points to graph.
For instance for the first graph, if x = 0, y = 5, that is one possible point. Keep on choosing x values to graph.