Question

Please answer below :-)

Answer 1

Step-by-step explanation:

$\frac{2x - 1}{4} + \frac{x}{3} = 2$

find a common denominator of 12 for each fraction

$\frac{3}{3} \times \frac{(2x - 1)}{4} + \frac{4}{4} \times \frac{x}{3} = \frac{12}{12} \times \frac{2}{1}$

$\frac{6x - 3}{12} + \frac{4x}{12} = \frac{24}{12}$

$\frac{6x - 3 + 4x}{12} = \frac{24}{12}$

$\frac{10x - 3}{12} = \frac{24}{12}$

multiply both sides by 12

$12 \times \frac{10x - 3}{12} = \frac{24}{12} \times 12$

12s cancel out

$10x - 3 = 24$

add three to both sides

$10x - 3 + 3 = 24 + 3$

$10x = 27$

divide both sides by 10

$\frac{10x}{10} = \frac{27}{10}$

The tens on the left side cancel

$x = \frac{27}{10} = 2.7$