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3 years ago

-r -10r heeeeeeeeeeeeeelllllppppp

Mathematics

2 answers:

nadya68 [22]3 years ago

8 0

Hey there!

-r - 10r

= -1r - 10r

COMBINE the LIKE TERMS

= (-1 - 10r)

= -11r

Therefore, your answer is: -11r

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Olin [163]3 years ago

7 0

Combine like terms:

-r-10r

We can always add variables as long as they are the same. So we can not add 10x+20y. That's impossible.

We can't add 3r^2+10r. That's also impossible.

However, we have the same variable, r. So we can add -r-10r. And the answer is:

-11r

Hope this helps! :)

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What does A equal: 3(6a+12)=9

melisa1 [442]

Answer:

a = -3/2

Step-by-step explanation:

3(6a+12)=9

Divide each side by 3

3/3(6a+12)=9/3

6a+12 = 3

Subtract 12 from each side

6a+12-12 = 3-12

6a = -9

Divide by 6

6a/6 = -9/6

a = -3/2

5 0

2 years ago

Read 2 more answers

Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4

ad-work [718]

Answer:

$f''(x)=36x^2+4$

Step-by-step explanation:

Let's start by finding the first derivative of $f(x)= 3x^4+2x^2-8x+4$ . We can do so by using the power rule for derivatives.

The power rule states that:

$\frac{d}{dx} (x^n) = n \times x^n^-^1$

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

$\frac{d}{dx} (3x^4+2x^2-8x+4)$

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)$

Simplify the equation.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)$
$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)$

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)$
$f'(x)=12x^3+4x-8$

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).

$\frac{d}{d} (f'x) = \frac{d}{dx} (12x^3+4x-8)$

$\frac{d}{dx} (12x^3+4x-8) = ((3)12x^3^-^1 + (1)4x^1^-^1 - (0)8)$

Simplify the equation.

$\frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4x^0 - 0)$
$\frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4(1) - 0)$
$\frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4 )$

Therefore, this is the 2nd derivative of the function f(x).

We can say that: $f''(x)=36x^2+4$

6 0

2 years ago

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3 years ago

-r -10r heeeeeeeeeeeeeelllllppppp​

-r -10r heeeeeeeeeeeeeelllllppppp