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Valentin [98]
3 years ago
6

A8 multipled by 3b is c730 what is a b anc c

Mathematics
1 answer:
Norma-Jean [14]3 years ago
4 0

Answer: A8 3b c730

Step-by-step explanation: The number A8 is a two-digit number with tens digit A and units (ones) digit 8. Similarly, 3B is a two-digit number with tens digit 3 and units digit B. When A8 is multiplied by 3B, the result is the four-digit number C730.

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If she saves 1$ the first week 3$ the season week 9$ the third week how much will she save in 5 weeks
ycow [4]

Based on the numbers we have we can assume that she saves 3 times more each week than the last (1*3=3, 3*3=9).

Following this trend we would multiply the amount she saved the third week ($9) by 3 to get $27 for the fourth week.

Then, we would multiply the amount she saved the fourth week ($27) by 3 to get $81 for the fifth week.

Finally, to figure out how much she saved in the 5 weeks, we need to add each value up to get 1+3+9+27+81= $121 saved in 5 weeks

5 0
3 years ago
Can someone help me with this pls ?
Eduardwww [97]

Answer:

D. The cost of the pizza with one topping costs $6.

5 0
3 years ago
Name the property 3. 7/9* 1= 7/9 ​
Nutka1998 [239]

Answer:

identify-multiplication

Step-by-step explanation:

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6 0
3 years ago
Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho
Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10

P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]

As, P(z>1.28)=0.10  [By z-table]

Then,

\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0
4 years ago
If someone could do this exam for me I'll do anything else school related!
trapecia [35]
C. just shorten fraction and you'll only get 1/(y²z²)
you'll get (6xy²z²)/(6xy⁴z⁴)=1/(y²z²)
3 0
3 years ago
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