Answer: D. Getting at least 2 heads and Getting at least 2 tails
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Explanation:
Choice A is not disjoint because "getting at least 1 tail" could have the sequence TTH. We see that we have two tails and exactly one head. So the events "getting exactly 1 head" and "Getting at least 1 tail" are possible to occur at the same time; therefore, they aren't disjoint events. Disjoint events are two events that cannot occur simultaneously. An example would be flipping heads and tails on the same coin at the same time.
Choice B is also not disjoint. We could have the sequence THT, which has at least one head and at least one tail. "At least" means that amount or more.
Choice C is also not disjoint. We could have the sequence HTT. This has exactly one head and at least two tails.
Choice D is the only thing left. It must be the answer. It is not possible to get 2 heads and 2 tails when Roger only flips the coin 3 times. He would need to flip the coin at least 4 times for this to happen. The portions "at least" don't even need to be considered. So this shows how choice D is disjoint.
B.
because of how the slope (Y over X) is 1/4 and the intercept is (0, 2).
The slope is positive because the line moves to the right.
(for me I remember that /it hurts \doesn't. The line is you moving your arm.)
The angle 86 makes the tan 14.3
4 * side^2 = diagonal1 ^2 + diagonal2 ^2
4 * side^2 = 24^2 + 10^2
4 * side^2 = 576 + 100
4 * side^2 = 676
side^2 = 169
side = 13
So, the perimeter of this rhombus = 4 * 13 = 52 cm
