The area of a right angled triangle with sides of length 9cm, 12cm and 15cm in square centimeters is 54 sq cm.
The formula to calculate the area of a right triangle is given by:
Area of Right Triangle, A = (½) × b × h square units
Where, “b” is the base (adjacent side) and “h” is the height (perpendicular side). Hence, the area of the right triangle is the product of base and height and then divide the product by 2.
We know that the hypotenuse is the longest side. So, the area of a right angled triangle will be half of the product of the remaining two sides.
Given sides of the triangle:
a=9cm
b=12cm
c=15cm
From this we know that the hypotenuse is c. Are of the triangle will be obtained by the other two sides.
∴Area =
x 9 x 12
= 54
Answer:
13058.83 cubic inches
Step-by-step explanation:
Given that a rectangular box is having dimensions as 41x81 inches.
Let x be the side of square cut from all the four corners.
The open box made would have height as x and length 41-2x with width 81-2x
Volume =

Equate first derivative to 0
We get applicable root as x = 8.642
Max volume = 13058.83 cubic inches
Answer:
l = 24ft
Step-by-step explanation:
A = lw
360 = (x + 9)(x)
360 = x^2 + 9x
0 = x^2 + 9x - 360
0 = (x + 24)(x - 15)
x ≠ -24 (length cannot be negative)
x = 15
l = 15 + 9
l = 24ft
Answer:
10%
Step-by-step explanation: