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3 years ago

Help help help …..please

Mathematics

2 answers:

givi [52]3 years ago

8 0

9.16515188
To find that all u do is square root it and then you will get ur answer because the “backwards ways” of squaring is square rooting

Sever21 [200]3 years ago

3 0

Answer:

9.16515138991

Round of :-

9.17...ans

Step-by-step explanation:

<h2>HOPE IT HELPS U!!!! </h2>

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A student's grades in the three tests in College Algebra are 85, 60, and 69. a) How many points does the student need on the fin

Anastaziya [24]

Answer:

(a) The student need 82 points on the final to average 74.

(b) The student must score 41 points on the final, assuming that the final carries double the weight.

Step-by-step explanation:

We are given that a student's grades in the three tests in College Algebra are 85, 60, and 69.

As we know that the formula for calculating the average of numbers is given by;

Average (Mean) = $\frac{\text{Sum of all values}}{\text{Number of observations}}$

(a) Let the points student need on the final test to average 74 be ' $x$ '.

So, Average of all four test = $\frac{85+60+69+x}{4}$

$74 = \frac{85+60+69+x}{4}$

$74 = \frac{214+x}{4}$

$214+x =74 \times 4$

$x = 296-214$

$x=82$

Hence, the student needs 82 points on the final to average 74.

(b) It is given that the final carries double the weight, this means that let the points student need on the final test to average 74 be ' $2x$ '.

So, Average of all four test = $\frac{85+60+69+2x}{4}$

$74 = \frac{85+60+69+2x}{4}$

$74 = \frac{214+2x}{4}$

$214+2x =74 \times 4$

$2x = 296-214$

$x=\frac{82}{2}$ = 41

Hence, the student must score on the final 41 points, assuming that the final carries double the weight.

7 0

3 years ago

F(x)=2x-6 answer please

kolezko [41]

Answer:

well that's already the slope and your i-intercept would be -6

Step-by-step explanation:

4 0

2 years ago

In a class of 30 students (x+10) study algebra, (10x+3) study statistics, 4 study both algebra and statistics. 2x study only alg

Vladimir [108]

Answer:

1. The Venn diagrams are attached

2. When the statistics students number = 10·x + 3, we have;

The number of students that study

a. Algebra = 128/11

b. Statistic = 213/11

When the statistics students number = 2·x + 3, we have;

The number of students that study

a. Algebra = 16

b. Statistic = 15

Step-by-step explanation:

The parameters given are;

Total number of students = 30

Number of students that study algebra n(A) = x + 10

Number of students that study statistics n(B) = 10·x + 3

Number of student that study both algebra and statistics n(A∩B) = 4

Number of student that study only algebra n(A\B) = 2·x

Number of students that study neither algebra or statistics n(A∪B)' = 3

Therefore;

The number of students that study either algebra or statistics = n(A∪B)

From set theory we have;

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 30 - 3 = 27

Therefore, we have;

n(A∪B) = x + 10 + 10·x + 3 - 4 = 27

11·x+13 = 27 + 4 = 31

11·x = 18

x = 18/11

The number of students that study

a. Algebra

n(A) = 18/11 + 10 = 128/11

b. Statistic

n(B) = 213/11

Hence, we have;

n(A - B) = n(A) - n(A∩B) = 128/11 - 4 = 84/11

Similarly, we have;

n(B - A) = n(B) - n(A∩B) = 213/11 - 4 = 169/11

However, assuming n(B) = (2·x + 3), we have;

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 30 - 3 = 27

Therefore, we have;

n(A∪B) = x + 10 + 2·x + 3 - 4 = 27

2·x+3 + x + 10= 27 + 4 = 31

3·x = 18

x = 6

Therefore, the number of students that study

a. Algebra

n(A) = 16

b. Statistics

n(B) = 15

Hence, we have;

n(A - B) = n(A) - n(A∩B) = 16 - 4 = 12

Similarly, we have;

n(B - A) = n(B) - n(A∩B) = 15 - 4 = 11

The Venn diagrams can be presented as follows;

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3 years ago

Find the constant of proportionality in the equation y=rx <br><br> R = ______

uranmaximum [27]

R is 1 because in the table nothing has change.

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