This is all about proportions. You can make this into fractions:
3/5 = 12/x
A good way to handle this, is to make one of those numbers the same. If you do (3/5) * 4, you would get 12/20 (because 4 * 3 = 12 and 4 * 5 = 20)
So then you have this:
12/20 = 12/x
It's basically a fill in the blank from there. x= 20
Elena's team played 20 games
It would be C because you don’t know how many watches so there is a variable, x. Then the price has to be less then or equal to because the amount is the most she can use so it can’t be greater.
Answer:
the answer should be positive 2 I could be wrong
Step One
Find the base area of the large hexagon as though the smaller one was not removed.
Area = 3*Sqrt(3) * a^2 /2 where a is the length of one side of the hexagon
a = 5
Area = 3*sqrt(3) * 25/2 = 75 sqrt(3) / 2 of the large hexagon without the smaller one removed.
Step Two
Find the area of the smaller hexagon. In this case a = 4
Area2 = 3*sqrt(3)*16/2 = 3*sqrt(3)*8 = 24 sqrt(3)
Step Three
Find the area of the thick hexagonal area left by the removal of the small hexagon.
Area of the remaining piece = area of large hexagon - area of the small hexagon
Area of the remaining piece = 75 *sqrt(3)/2 - 24*sqrt(3)
Step Four
Find the volume of the results of the area from step 3
Volume = Area * h
h = 18
Volume = (75 * sqrt(3)/2 - 24*sqrt(3))* 18
I'm going to leave you with the job of changing all of this to a decimal answer. I get about 420 cm^3
