The probability you're asked to find is
where
is the event that either event occurs (A, B, or both), and
is the event that both events occur.
Recall that
which means
You're told that
,
, and (if I'm reading the diagram correctly)
.
So,
Another way of seeing this is that the event A consists of the regions "A not B" and "A and B". So the probability that "A not B" occurs is
Similarly, B consists of "B not A" and "A and B", so you have
So the probability that A or B, but not both, occur is
Answer:
<h3>She will invest a lot of money.</h3>
Step-by-step explanation:
<h2>24+<em>y</em>=your answer! Hope it helped! :)</h2>
Answer:
OD) 4.9 units, 14.2 units
<em> The lengths of the legs of a right triangle</em>
<em> </em>a = 4.9units , b = 14.2units and hypotenuse 'c' = 15
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the Acute angle is 19°
And hypotenuse (AC ) = c= 15
We will take cos∝ =
⇒
⇒ BC = 15 × cos 19°
⇒ BC = 15 ×0.9455
⇒ BC = 14.18
The length of the one leg of the right angle triangle
BC = b = 14.18≅ 14.2
We know that ΔABC is a right angle triangle
a² = c² - b²
= 15² - (14.18)²
= 225 - 201.07
= 23.93
a² = 23.93
a = √23.93 = 4.89≅4.9
<u><em>Final answer:-</em></u>
<em> The lengths of the legs of a right triangle</em>
<em> </em>a = 4.9units , b = 14.2units and hypotenuse 'c' = 15
Answer:
59.
Step-by-step explanation:
I´m pretty sure the answer is 59. If I´m wrong then sorry.