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Delvig [45]
3 years ago
9

Nick and Linda are paid 33.25 for their work. Nick worked 1.5 hours, and Linda worked 2 hours. They split the money according to

the amount of time each of them worked. How much is Nick's share of the money?
Mathematics
1 answer:
8090 [49]3 years ago
8 0

Answer

the money is 12.75.

38.25 ÷ 4.5 = 8.5

8.5 · 1.5 = 12.75

Step-by-step explanation:

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Solve: 8.2 = 3.4 + d d = _____
Alinara [238K]

Answer:

4.8

Step-by-step explanation:

You just subtract to solve for d so,

8.2 = 3.4 + d

-3.4   -3.4

4.8 = d

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Help me pls ill give extra points
olga55 [171]

Answer:

y = x + 1

Step-by-step explanation:

We are using the points (0, 1) and (6, 7). First, use these points to find the slope.

m = y₁ - y₂/x₁ - x₂

⇒ m = 7 - 1/6 - 0

⇒ m = 6/6

⇒ m = 1

Now that we know the slope is one, enter the values into the point-slope form equation. I'll use (0, 1) in this instance.

y - y₁ = m(x - x₁)

⇒ y - 1 = 1(x - 0)

⇒ y - 1 = x

⇒ y = x + 1

Therefore, the equation is y = x + 1.

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I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
4 years ago
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