Using it's vertex, the maximum value of the quadratic function is -3.19.
<h3>What is the vertex of a quadratic equation?</h3>
A quadratic equation is modeled by:
![y = ax^2 + bx + c](https://tex.z-dn.net/?f=y%20%3D%20ax%5E2%20%2B%20bx%20%2B%20c)
The vertex is given by:
![(x_v, y_v)](https://tex.z-dn.net/?f=%28x_v%2C%20y_v%29)
In which:
Considering the coefficient a, we have that:
- If a < 0, the vertex is a maximum point.
- If a > 0, the vertex is a minimum point.
In this problem, the equation is:
y + 4 = -x² + 1.8x
In standard format:
y = -x² + 1.8x - 4.
The coefficients are a = -1 < 0, b = 1.8, c = -4, hence the maximum value is:
![y_v = -\frac{1.8^2 - 4(-1)(-4)}{4(-1)} = -3.19](https://tex.z-dn.net/?f=y_v%20%3D%20-%5Cfrac%7B1.8%5E2%20-%204%28-1%29%28-4%29%7D%7B4%28-1%29%7D%20%3D%20-3.19)
More can be learned about the vertex of a quadratic function at brainly.com/question/24737967
#SPJ1
Answer:
(1, 4)
Step-by-step explanation:
y=x+3
y=3x+1
y=x+3
x+3=3x+1
x=3x-2
-2x=-2
x=1
y=1+3
y=4
Answer:
62%
Step-by-step explanation:
Hey there!
2.7 * 10^4 + 120
10^4
= 10 * 10 * 10 * 10
= 100 * 100
= 10,000
2.7 * 10,000 + 120
= 27,000 + 120
= 27,120
Therefore, your answer is. [10,000 * 2.712] because 10,000 * 2.712 is approximately 27,120
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)