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2 years ago

What is the slope of the line whose equation is –3x+y=12

Mathematics

1 answer:

hammer [34]2 years ago

5 0

Answer:

m=3 is the slope

Step-by-step explanation:

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Convert 111110 base two to base eight

Gre4nikov [31]

Answer: I got 76.

Step-by-step explanation:

8 0

3 years ago

Barbra can walk 3200 meters in 24 minutes. How far can she walk in 3 minutes show your work

vichka [17]

$\frac{3200}{24}=\frac{n}{3}\\\frac{3200}{24}/\frac{8}{8}=\frac{n}{3}\\\frac{400}{3}=\frac{n}{3}\\\frac{400}{3}*3=\frac{n}{3}*3\\400=n\$

400 meters

3 0

3 years ago

2x ≤ 12 Select the appropriate response A2x ≤ 12 B)x≤4 C)x≤6 D)x ≤ 10

Monica [59]

Answer:

c x ≤ 6

Step-by-step explanation:

2x ≤ 12

Divide each side by 2

2x/2 ≤ 12/2

x ≤ 6

8 0

3 years ago

Given: y" - 2y' = 6t + 5e^2t. Find the correct form to use for y_p if the equation is solved using Undetermined coefficients. Do

const2013 [10]

Answer:

$y_p=A+Bt+Ce^{2t}$

Step-by-step explanation:

Given: $y'' - 2y' = 6t + 5e^{2t}$ .

we need to find the correct form for $y_p$ if the equation is solve using undetermined coefficients.

A first order differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}=f\left ( x,y \right )$ is said to be homogeneous if $f(tx,ty)=f(x,y)$ for all t.

Consider homogeneous equation $y''-2y'=0$

Let $y=e^{rt}$ be the solution .

We get $(r^2-2r)e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2-2r=0$ .

So, we get solution as $y_c=c_1+c_2e^{2t}$

As constant term and $e^{2t}$ are already in the R.H.S of equation

$y" - 2y' = 6t + 5e^{2t}$ , we can take $y_p$ as $y_p=A+Bt+Ce^{2t}$

6 0

3 years ago

A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic

Rina8888 [55]

Answer:

The probability that none of the LED light bulbs are defective is 0.7374.

Step-by-step explanation:

The complete question is:

What is the probability that none of the LED light bulbs are defective?

Solution:

Let the random variable X represent the number of defective LED light bulbs.

The probability of a LED light bulb being defective is, P (X) = p = 0.03.

A random sample of n = 10 LED light bulbs is selected.

The event of a specific LED light bulb being defective is independent of the other bulbs.

The random variable X thus follows a Binomial distribution with parameters n = 10 and p = 0.03.

The probability mass function of X is:

$P(X=x)={10\choose x}(0.03)^{x}(1-0.03)^{10-x};\ x=0,1,2,3...$

Compute the probability that none of the LED light bulbs are defective as follows:

$P(X=0)={10\choose 0}(0.03)^{0}(1-0.03)^{10-0}$

$=1\times 1\times 0.737424\\=0.737424\\\approx 0.7374$

Thus, the probability that none of the LED light bulbs are defective is 0.7374.

6 0

3 years ago