Answer:
Explanation:
A. Max is correct But min will be max(N1,N2) i.e. N2.
B. max=N1, min=0(no common tuples in R1 and R2)
C. max=N1(R1 and R2 are disjoint sets), min=0(all tuples of R1 are present in R2)
D. max=N1*N2, min=N1*N2
Answer:
a b c
Explanation:
they can report data from these three options
Answer:
Explanation:
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Rehabilitation Engineering.
Answer:
#include <iostream>
#include<iomanip>
using namespace std;
double DrivingCost(double drivenMiles, double milesPerGallon, double dollarsPerGallon)
{
double dollarCost = 0;
dollarCost = (dollarsPerGallon * drivenMiles) / milesPerGallon;
return dollarCost;
}
int main()
{
double miles = 0;
double dollars = 0;
cout << "Enter miles per Gallon : ";
cin >> miles;
cout << "Enter dollars per Gallon: ";
cin >> dollars;
cout << fixed << setprecision(2);
cout << endl;
cout << "Gas cost for 10 miles : " << DrivingCost(10, miles, dollars) << endl;
cout << "Gas cost for 50 miles : " <<DrivingCost(50, miles, dollars) << endl;
cout << "Gas cost for 400 miles: "<<DrivingCost(400, miles, dollars) << endl;
return 0;
}
Explanation:
- Create a method definition of DrivingCost that accepts three input double data type parameters drivenMiles, milesPerGallon, and dollarsPerGallon and returns the dollar cost to drive those miles
.
- Calculate total dollar cost and store in the variable, dollarCost
.
- Prompt and read the miles and dollars per gallon as input from the user
.
- Call the DrivingCost function three times for the output to the gas cost for 10 miles, 50 miles, and 400 miles.
