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2 years ago

What is the square root of 49 giving brainliest

Mathematics

2 answers:

natulia [17]2 years ago

7 0

$\\ \sf\longmapsto \sqrt{49}$

$\\ \sf\longmapsto \sqrt{7\times 7}$

$\\ \sf\longmapsto \sqrt{7^2}$

$\\ \sf\longmapsto 7$

tia_tia [17]2 years ago

4 0

Answer:

Step-by-step explanation:

here 7×7 = 49

So the square root of 49 is 7.

Hope it helps you!!

#IndianMurgaツ

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Explanation:

From the given graph, we can see that the equation of the inequalities are

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To determine the coordinate that satisfies the inequality, let us substitute the coordinates in both of the inequalities $y>-x+1$ and $$y$

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Option A: $(1,-1)$

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$$y\leq 2 x+3 \implies -1\leq 5$ is true.

Since, only one equation satisfies the condition, the coordinate $(1,-1)$ is not a solution.

Hence, Option A is not the correct answer.

Option B: $(-4,0)$

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$ , we get,

$y>-x+1\implies0>5$ is not true.

$$y\leq 2 x+3 \implies 0\leq -5$ is not true.

Since, both the equations does not satisfy the condition, the coordinate $(-4,0)$ is not a solution.

Hence, Option B is not the correct answer.

Option C: $(3,-2)$

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$ , we get,

$y>-x+1\implies-2>-2$ is not true.

$$y\leq 2 x+3 \implies -2\leq 9$ is true.

Since, only one equation satisfies the condition, the coordinate $(3,-2)$ is not a solution.

Hence, Option C is not the correct answer.

Option D: $(0,3)$

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$ , we get,

$y>-x+1\implies3>1$ is true.

$$y\leq 2 x+3 \implies 3\leq 3$ is true.

Since, both equation satisfies the condition, the coordinate $(0,3)$ is a solution.

Hence, Option D is the correct answer.

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