Question

Help me with this math problem

Answer 1

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Let's solve :

by using Pythagoras theorem :

• EF² = EG² - GF²

• EF² = ${\sqrt{}{24}}^{2}$ - 3²

• EF² = 24 - 9

• EF² = 15

• EF = ${\sqrt{}{15}}$

now,

• $\tan(G) = \dfrac{ \sqrt{15} }{3}$

• $\tan(G) = \dfrac{3.873}{3}$

• $\tan(G) = 1.291$

• $\tan(G) \approx1.29$

Answer 2

Answer:

tan A = opp

adj

tan G = EF

3

from Pythagoras theorem,

EF² + 3² = (√24)²

EF² + 9 = 24

EF² = 15

EF = √15

then,

tan G = √15

3

therefore tan G = √15/3