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neonofarm [45]
3 years ago
10

Triangle K M L is shown. Line L K extends through point J to form exterior angle J K M. Which statement regarding the diagram is

true? m∠MKL m∠MLK = m∠JKM m∠KML m∠MLK = m∠JKM m∠MKL m∠MLK = 180° m∠JKM m∠MLK = 180°
SAT
1 answer:
MatroZZZ [7]3 years ago
8 0

The exterior angle of a triangle is the sum of the opposite interior angles.

The true statement is: \mathbf{(b)\ \angle JKM = \angle KML + \angle MLK}

From the figure (see attachment), we have:

∠JKM as an exterior angle to ∠KML and ∠MLK

In a triangle,

The exterior angle equals the sum of the opposite interior angles.

This means that:

\mathbf{\angle JKM = \angle KML + \angle MLK}

Hence, the true statement is: \mathbf{(b)\ \angle JKM = \angle KML + \angle MLK}

Read more about exterior and interior angles at:

brainly.com/question/14790214

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Waylon works for a company that produces temporary tattoos. His company wants to reach a young, highly engaged target market. Hi
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The social media platform that Waylon should invest more resources into is the one that has a platform  that has a lot of followers in the aspect of their target market ( the ones that showcase more of temporary tattoos)

<h3>What is an investment?</h3>

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7 0
3 years ago
a 15.0 kg block is attached to a very light horizontal spring of force constant 575 n/m and is resting on a smooth horizontal ta
Luden [163]

The instantaneous velocity of the 15 kg. mass just after collision can be found by the principle of linear momentum.

a) The speed of the 15 kg. just after collision is <u>2 m/s</u>.

b) The type of collision is <u>inelastic collision</u>

c) The compression of the spring is approximately <u>0.323 m</u>.

Reasons:

The given parameters are;

Mass of the block attached to the spring, m₁ = 15.0 kg

Force constant of the spring, K = 575 N/m

Mass of the stone that strikes the block, m₂ = 3.00 kg

Speed of the stone, v₂ = 8.00 m/s

Speed with which the stone rebounds, v₃ = 2.00 m/s

a) The total initial momentum = 3 kg. × 8 m/s = 24 kg·m/s

The final momentum, just after collision = 3 × (-2) kg·m/s + 15 kg ×v₁

By conservation of momentum, we have;

24 kg·m/s = 3 × (-2) kg·m/s + 15 kg ×v₁

v_1 = \dfrac{24 \, kg \cdot m/s +  6  \, kg \cdot m/s}{15 \, kg}  = 2 \, m/s

The speed of the 15 kg. just after collision, v₁ = <u>2 m/s</u>.

b) A collision is elastic when the kinetic energy of the collision is conserved

The initial kinetic energy, K.E.₁ = 0.5 × 3 kg. ×(8 m/s)² = 96 J

The sum of the final kinetic energy are;

0.5 × 3 kg. ×  (2 m/s)² + 0.5 × 15 kg ×  (2 m/s)² = 36 J

The initial kinetic energy ≠  The final kinetic energy

Therefore, <u>the collision is not elastic</u>

(c) The kinetic energy given by the block = The elastic potential energy gained by the spring

Kinetic energy of the block, K.E. = 0.5 × 15 kg ×  (2 m/s)² = 30 J

Elastic energy gained by the block = 0.5 × K × x² = 0.5 × 575 N/m × x²

Therefore;

0.5 × 575 N/m × x² = 30 J

x^2 = \dfrac{30 \, J}{0.5 \times 575 \, N/m} = \dfrac{12}{115} \, m^2

x = 2 \cdot \sqrt{\dfrac{3}{115} } \approx 0.323

The compression of the spring, <em>x</em> ≈ <u>0.323 m</u>.

Learn more here:

brainly.com/question/7694106

<em>Questions;</em>

<em>(a) The speed of the 15 kg mass immediately after the collision</em>.

<em>(b) Determine the type of collision; Elastic or inelastic collision</em>.

<em>(c) The distance to which the spring is compressed by the block</em>.

3 0
3 years ago
based on the graph, predicted population growth in which of the following regions is explained by a high total fertility rate?
kotegsom [21]

Answer:

None of them

Explanation:

because there is no graph hence nothing can be done

5 0
3 years ago
A craft vendor must sell at least $300 worth of merchandise to make a profit. Scarves sell for $10 each and hats sell for $20 ea
ICE Princess25 [194]

Answer:

The answer is 1.

Explanation: I just got it on Edge.

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