Solve for x! Someone helppp

Mathematics

1 answer:

olganol [36]2 years ago

6 0

Answer:

17.2

Step-by-step explanation:

8.7x-1.9x=116.96

6.8x=116.96

x=116.96/6.8

x= 17.2

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8/10x 1 3/5 =? would be what?

Aleonysh [2.5K]

8/10 x 1 3/5 = ?
first u need to find the mixed fraction is 8/5: 1 3/5 = 8/5
8/10 x 8/5 = 64/50
64/50 in simplest form: 32/25
32/25 equals to 1 7/25
so the answer is 1 and 7/25

6 0

3 years ago

What are the first 5 terms of the sequence where a=1 a, a2=2 and an=1/2(a n-1•a n-2)

Sliva [168]

Answer:

$\large\boxed{a.\ 1,\ 2,\ 1,\ 1,\ \dfrac{1}{2}}$

Step-by-step explanation:

We have the recursive formula of a sequence:

$\left\{\begin{array}{ccc}a_1=1\\a_2=2\\a_n=\dfrac{1}{2}(a_{n-1}\cdot a_{n-2})\end{array}\right\\\\\text{thereofre}\\\\a_3=\dfrac{1}{2}(a_2\cdot a_1)=\dfrac{1}{2}(2\cdot1)=\dfrac{1}{2}(2)=1\\\\a_4=\dfrac{1}{2}(a_3\cdot a_2)=\dfrac{1}{2}(1\cdot2)=\dfrac{1}{2}(2)=1\\\\a_5=\dfrac{1}{2}(a_4\cdot a_3)=\dfrac{1}{2}(1\cdot1)=\dfrac{1}{2}(1)=\dfrac{1}{2}$

7 0

3 years ago

Without using a calculator, match each expression to the correct point.

solniwko [45]

Answer:

The locations of each irrational number are the following:

$\sqrt{16}$ - Point $a$

$\sqrt{27}$ - Point $b$

$\sqrt{32}$ - Point $c$

Step-by-step explanation:

$\sqrt{16}$ is an irrational number that is also rational, since $4^{2} = 16$ . Then, $\sqrt{16}$ must be point $a$ .

Both $\sqrt{27}$ and $\sqrt{32}$ are greater than $\sqrt{25} = 5$ and less than $\sqrt{36} = 6$ . Then, both are between 5 and 6. Since $\sqrt{27} < \sqrt{32}$ , $\sqrt{27}$ must be point $b$ and $\sqrt{32}$ must be point $c$ .