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nevsk [136]
3 years ago
6

13 add (-20) answer plz

Mathematics
2 answers:
8090 [49]3 years ago
7 0

Step-by-step explanation:

13 + (-20) = 13 - 20 = -7

HOPE IT HELPS

Aneli [31]3 years ago
3 0

Answer:

-7

Step-by-step explanation:

I'd recommend at least trying the problem before asking for help. This is a simple subtraction/addition problem.

13 add (-20) is 13 + (-20), which is 13 - 20.

13-20 = -7

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(−1) to the power of 3
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-(1) * (-1) * (-1)

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Central City High’s basketball team will be entering the playoffs at the end of their regular season. There will be 3 other team
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Given the domain {-4, 0, 5}, what is the range for the relation 12x 6y = 24? a. {2, 4, 9} b. {-4, 4, 14} c. {12, 4, -6} d. {-12,
xz_007 [3.2K]

The domain of the function 12x + 6y = 24 exists {-4, 0, 5}, then the range of the function exists {12, 4, -6}.

<h3>How to determine the range of a function?</h3>

Given: 12x + 6y = 24

Here x stands for the input and y stands for the output

Replacing y with f(x)

12x + 6f(x) = 24

6f(x) = 24 - 12x

f(x) = (24 - 12x)/6

Domain = {-4, 0, 5}

Put the elements of the domain, one by one, to estimate the range

f(-4) = (24 - 12((-4))/6

= (72)/6 = 12

f(0) = (24 - 12(0)/6

= (24)/6 = 4

f(5) = (24 - 12(5)/6

= (-36)/6 = -6

The range exists {12, 4, -6}

Therefore, the correct answer is option c. {12, 4, -6}.

To learn more about Range, Domain and functions refer to:

brainly.com/question/1942755

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7 0
2 years ago
Susan made $117 for hours 9 of work.
Irina18 [472]
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8 0
3 years ago
A survey by the Pew Research Center asked a random sample of 2142 U.S. adults and a random sample of 1055 college presidents how
gayaneshka [121]

Answer: 0.0125

Step-by-step explanation:

Given :  A survey by the Pew Research Center asked a random sample of 2142 U.S. adults and a random sample of 1055 college presidents how they would "rate the job the higher education system is doing in providing value for the money.

5% the U.S. adults and 17% of the college presidents provided a rating of "Excellent."

i.e. n_1=2142,\ n_2=1055

p_1=0.05 , p_2=0.17

The standard error of the difference in sample proportions  :-

\sqrt{\dfrac{p_1(1-p_1)}{n_1}+\dfrac{p_2(1-p_2)}{n_2}}

=\sqrt{\dfrac{0.05(1-0.05)}{2142}+\dfrac{0.17(1-0.17)}{1055}}\\\\=0.0124867775151\approx0.0125

Hence, the standard error of the difference in sample proportion = 0.0125

5 0
3 years ago
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