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2 years ago

12

A quadratic function is increasing on the interval x>4 and decreasing on the interval x<4. It has a minimum value of 1 and

passes through the point (2,11). Determine the equation for this parabola

1 answer:

statuscvo [17]2 years ago

5 0

O si la verdad esa la multiplicas por cada forma

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Question 5 (1 point)

fredd [130]

Answer:

a) x² + 6x + 9

Step-by-step explanation:

When we square something, we multiply it by itself:

⇒ (x + 3)² = (x + 3)(x + 3)

Using the FOIL method: (a + b)(c + d) = ac + ad + bc + bd

⇒ (x + 3)(x + 3) = x² + 3x + 3x + 9

= x² + 6x + 9

4 0

2 years ago

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What is the side length , in inches, of the pet shop sign ?

rusak2 [61]

Could i see a picture please

7 0

3 years ago

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Solve for 2x^2-4x+5=6

Softa [21]

To solve for a variable, you need to get it (x) by itself.

2x² - 4x + 5 = 6 Subtract 6 from both sides
2x² - 4x - 1 = 0 Plug this into the Quadratic Formula

a = 2 , b = -4 , c = -1
x = $\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ Plug in your values
x = $\frac{-(-4) \pm \sqrt{(-4)^2 - 4(2)(-1)} }{2(2)}$ Simplify
x = $\frac{4 \pm \sqrt{16 + 8} }{4}$ Simplify
x = $\frac{4 \pm 2\sqrt{6} }{4}$ Simplify by removing a 2 from every term
x = $\frac{2 \pm \sqrt{6} }{2}$ Simplify by taking the fraction apart
x = $\frac{2}{2} \pm \frac{ \sqrt{6} }{2}$ Change $\frac{2}{2}$ to 1
x = 1 $\pm \frac{ \sqrt{6} }{2}$ Simplify $\frac{ \sqrt{6} }{2}$ to $\sqrt{ \frac{3}{2} }$
x = 1 $\pm \sqrt{ \frac{3}{2} }$

4 0

3 years ago

To which subsets of the real numbers does 22 belong to?

Vedmedyk [2.9K]

Whole number and integer

8 0

3 years ago

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A,B,C,D what’s the correct answer

zzz [600]

Answer:

C. 16

Explanation:

You find 4/6 of 24

4/6 x 24 = 96

Then you divide 96 by 6

96/6 = 16

You can check your work by doing 16 x 6

7 0

3 years ago

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