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3 years ago

Solve for k. k(4r−5)≥12r−9

Mathematics

1 answer:

amid [387]3 years ago

6 0

Answer:

$k = \frac{12r - 9}{4r - 5} \\$

Step-by-step explanation:

$k(4r - 5) \geqslant 12r - 9 \\ k = \frac{12r - 9}{4r - 5} \\$

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