Critical thinking is important to understand because:

riadik2000 [5.3K]

Exactly I feel you pls pls pls

7 0

2 years ago

A survey showed that 34 % of human resource professionals are at companies that rejected job candidates because of information

Svetllana [295]

Using the binomial distribution, it is found that since 16 is more than 2.5 standard deviations above the mean, it is a unusually high number.

<h3>What is the binomial probability distribution?</h3>

It is the probability of <u>exactly x successes on n repeated trials, with p probability</u> of a success on each trial.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

A measure is considered to be unusually high if it is more than 2.5 standard deviations above the mean.

In this problem, we hav ehtat:

34% of companies reject candidates because of information found on their social media, hence p = 0.34.

27 human resource professionals are randomly selected, hence n = 27.

Then, we find the threshold for unusually high values as follows:

E(X) = np = 27 x 0.34 = 9.18

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{27(0.34)(0.66)} = 2.46$

T = 9.18 + 2 x 2.46 = 14.1.

Since 16 is more than 2.5 standard deviations above the mean, it is a unusually high number.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

3 0

1 year ago

15. For a random sample of n = 64, find the probability of a sample mean being

mart [117]

Answer:

0.9726

Explanation:

The computation of the probability of a sample mean is shown below:

$P(\bar x < 24.3)$

To find the probability first we have to determine the z score which is

$z = \frac{\bar x - \mu_{\bar x}}{\sigma_{\bar x}} \\\\ = \frac{\bar x - \mu }{\frac{\sigma}{\sqrt{n} } } \\\\ = \frac{24.3 - 24}{\frac{1.25}{\sqrt{64} } }$

= 1.92

Now probability is

$P(\bar x < 24.3) \\\\= P(z < 1.92)$

= 0.9726

Hence, the probability of the sample mean is 0.9726

We simply applied the above formulas to determined the probability of a sample mean and the same is to be considered

6 0

2 years ago

What is the sum of the complex numbers 6+2i and 3+5i, where i=sqrt(-1)

m_a_m_a [10]

Answer:

The sum of the complex numbers is $9+i\,7$ .

Explanation:

Let be $u = 6 + i\,2$ and $v = 3 + i\,5$ , the sum of the complex number can be found by algebraic means. That is:

1) $u = 6 + i\,2$ , $v = 3 + i\,5$ Given.

2) $u+v = (6+i\,2)+(3+i\,5)$ Definition of addition.

3) $u+v = (6+3) + (2\,i + 5\,i)$ Commutative and associative properties.

4) $u+v = 9 + (2+5)\,i$ Definition of addition/Distributive property.

5) $u + v = 9 + i\,7$ Definition of addition/Commutative property/Result.

The sum of the complex numbers is $9+i\,7$ .

3 0

2 years ago

Use the sample data and confidence level given below to complete parts a through d.

4vir4ik [10]

Using the information given and the z-distribution, it is found that:

a) The point estimate of the population proportion is 0.5544.

b) The margin of error is: 0.0320.

c) The interval is: (0.5224, 0.5864).

d) The interpretation of the interval is: we are 95% sure that the true population proportion is between 0.5224 and 0.5864.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions has the bounds given by the rule presented as follows:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which the variables used to calculated these bounds are listed as follows:

$\pi$ is the point estimate of the population proportion.

z is the critical value.

n is the sample size.

The confidence level is of 95%, hence the critical value z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.