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Thepotemich [5.8K]
3 years ago
13

An analog video is a video signal transmitted by an analog signal, captured on a (blank)

Computers and Technology
1 answer:
Tju [1.3M]3 years ago
3 0

Answer:Analog component signals are comprised of three signals, analog R′G′B′ or YPbPr. Referred to as 480i (since there are typically 480 active scan lines per frame and they are interlaced), the frame rate is usually 29.97 Hz (30/1.001) for compatibility with (M) NTSC timing.

Explanation:

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Explanation:

solução de ácido clorídrico (HCI 6 m e HCI 0,6 m)

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3 years ago
What symbol do we use to denote a character?
pychu [463]

Answer:

'Single Character'

Explanation:

A Character, commonly abbreviated as "char", is a computer symbol, letter, or number. A keyboard is an input device that inputs a character when a key is pressed.

5 0
3 years ago
Which type of shape allows you to add text that can be moved around.
Kipish [7]

Answer:

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3 0
2 years ago
A company ABC asked you to design a simple payroll program that calculates and employee's weekly gross pay, including any overti
julsineya [31]

Answer:

<em>C++.</em>

#include <iostream>

using namespace std;

////////////////////////////////////////////////////////////////

int main() {

   int weekly_hours = 0;

   int hourly_rate;

   float gross_pay = 0;

   cout<<"Enter weekly hours worked: ";

   cin>>weekly_hours;

   

   cout<<"Enter hourly rate: ";

   cin>>hourly_rate;

   

   cout<<endl;

   ////////////////////////////////////////////////

   if (weekly_hours > 40) {

       gross_pay = (weekly_hours*hourly_rate) + ((weekly_hours*hourly_rate)*0.5);

   }

   else

       gross_pay = weekly_hours*hourly_rate;

       

   cout<<"Weekly gross pay: $"<<gross_pay;

   ////////////////////////////////////////////////

   return 0;

}

3 0
3 years ago
This program is to compute and write to a file the GPA for student scores read from an input file. The point values of the grade
VARVARA [1.3K]

Answer:

#Take input from the user

filename=input('Enter name of input file: ')

total_units=0#Total number of units for a student

total_score=0#Total score of a student

#Assign a score to each grade. I have reduced 0.33 for each grade. Change here if you need to

grade={'A':4.0,'A-':3.67,'B+':3.34,'B':3.01,'B-':2.68,'C+':2.35,'C':2.02,'C-':1.69,'D+':1.36,'D':1.03}

try:

with open(filename,"r") as input_file:#Open the file for input(reading)

output_file=open("GPA_output.txt","w") #Create and open GPA_output.txt if it doesn't exist for writing

for student_record in input_file:#read from input file

if("," in student_record):#if there is a , that means this is the student name

student_name=student_record.strip('\n')#Remove \n from student name

continue

else:

if(" " in student_record):#If a line contains spaces then its the student's grades for a course

student=student_record.split(" ")#Split to find the coursename, units and grade

#student[0]=coursename student[1]=units student[2]=grade

total_units+=int(student[1])#Calculate total units for 1 student

total_score+=int(student[1])*grade[student[2].strip('\n')]#Find the total score of a student

#grade[student[2]] will lookup for the score that we initialized earlier

#if student has a grade as A then this will look up as grade['A'] which will return 4

#Find the total score as product of this grade and units for this course

continue

else:

if(total_units>0):#Check if score has been calculated for a student earlier

print("in")

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

if(total_units>0):#Essential for the case when the file doesn't end with a new line(Check if total_units is not 0) which means a record is pending

#to be written to the file

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

input_file.close()#Close the input file

output_file.close()#Close the output file

except IOError as e:

print("Problem in Opening the required file")#Print a message if file cannot be opened

Explanation:

The program has been tested for all 3 scenarios mentioned i.e.

a. If the file ends without \n

b. If the file ends with 2 \n

c. If the file ends with 1 \n

PS: The Program will run irrespective of how it ends. Even if there are many \n at the end of file, the program will be fine.

3 0
3 years ago
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