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2 years ago

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HELPPP

1 answer:

Alexxandr [17]2 years ago

3 0

Hope this helps you

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Apply the distributive property to factor out the GCF.<br><br> 22c + 33d=________

slava [35]

Answer:

Step-by-step explanation:

3 0

3 years ago

Which statement is true about the expression 12- 7 + 3?

Mrrafil [7]

Answer:

I don't see any statements here.

Anyway, the answer is 8.

$12 - 7 + 3 = 8$

3 0

2 years ago

Each week, Rosario drives to an ice-skating rink that is 60 miles away. The round-trip takes 2. 75 hours. If he averages 55 mile

mart [117]

Rosario's average speed on her way home is 36.66 miles per hour.

<h2><u></u></h2><h2><u>Average speed</u></h2>

Given that each week, Rosario drives to an ice-skating rink that is 60 miles away, and the round-trip takes 2.75 hours, to determine, if she averages 55 miles per hour on his way to the rink, what is her average speed to return to his house, the following calculation must be made:

55 = 1
60 = X
60 / 55 = X
1.09 = X
2.75 - 1.09 = 1.66
55 = 1
27.5 = 2
55 / 3 x 2 = 36.66

Therefore, Rosario's average speed on her way home is 36.66 miles per hour.

Learn more about averages in brainly.com/question/12322912

4 0

2 years ago

Read 2 more answers

Find x<br><br><br><br><br> Thanks for the help in advance!

Marina86 [1]

I'm not sure if this is the easiest way of doing this, but it surely work.

Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

$AH=2,\quad HB=6,\quad AC=x$

Moreover, let CH=y and BC=z

Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

$\begin{cases}4+y^2=x^2\\36+y^2=z^2\\x^2+z^2=64\end{cases}$

If we solve the first two equations for y squared, we have

$y^2=x^2-4\\y^2=z^2-36$

And we can deduce

$z^2 = x^2+32$

So that the third equation becomes

$x^2+x^2+32=64 \iff 2x^2 = 32 \iff x^2=16 \iff x=4$

(we can't accept the negative root because negative lengths make no sense)

7 0

2 years ago

F(x)=x^2-1 <br> G(x)=x-1 <br> find (f+g)(10).

WARRIOR [948]

<h2>Adding Functions</h2><h3>Answer:</h3>

$(f +g)(10) = 108$

<h3>Step-by-step explanation:</h3>

Before we can solve for $(f +g)(10)$ , we need to know how $(f +g)(x)$ is defined.

$(f +g)(x) = f(x) +g(x) \\ (f +g)(x) = (x^2 -1) +(x -1) \\ (f +g)(x) = x^2 -1 +x -1 \\ (f +g)(x) = x^2 +x -2$

We can now solve for $(f +g)(10)$ :

$(f +g)(10) = (10)^2 +(10) -2 \\ (f +g)(10) = 100 +10 -2 \\ (f +g)(10) = 108$

6 0

2 years ago