A(n)=4+4(n-1)
a(n)=4+4n-4
a(n)=4n
76=4n
n=19
The sum of any arithmetic sequence (series are infinite) is:
(a+a(n))(n/2)
The average of the first and last terms times the number of terms, in this case we found that n=19 so:
19(4+76)/2=760
Some are
y-2=-3x
y+3x=2
3x=2-y
Answer:
i need this for a challenge
Step-by-step explanation:
Answer:
0.5 or 1/2
Step-by-step explanation
I dont know if they want the answer in fraction form.
