Expand 3(2y+1)<br><br> Answer this, please.

For the hypotheses below test alpha = 0.025 with n = 100 and bar p = 0.67. State

I am Lyosha [343]

Answer:

Part a : Critical value

For this case we want a value of $\alpha = 0.025$ we need to find on the normal standard distribution a z score that accumulates 0.025 of th area on the left and this value is $z_{crit}= -1.96$

Part b: Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.67 -0.76}{\sqrt{\frac{0.76(1-0.76)}{100}}}=-2.107$

Part c: Statistical decision

$n \hat p= 100*0.67= 67 >5$

$n (1-\hat p)= 100*(1-0.67)= 33 >5$

So then the normal approximation makes sense.

Since the calculated value is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level provided and we can conclude that the true proportion is lower than 0.76

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

$\hat p=0.67$ estimated proportion of interest

$p_o=0.76$ is the value that we want to test

$\alpha=0.025$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.76:

Null hypothesis: $p\geq 0.76$

Alternative hypothesis: $p < 0.76$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Part a : Critical value

For this case we want a value of $\alpha = 0.025$ we need to find on the normal standard distribution a z score that accumulates 0.025 of th area on the left and this value is $z_{crit}= -1.96$

Part b: Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.67 -0.76}{\sqrt{\frac{0.76(1-0.76)}{100}}}=-2.107$

Part c: Statistical decision

$n \hat p= 100*0.67= 67 >5$

$n (1-\hat p)= 100*(1-0.67)= 33 >5$

So then the normal approximation makes sense.

Since the calculated value is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level provided and we can conclude that the true proportion is lower than 0.76

6 0

4 years ago

Help me please ... im stuck on my hw

miss Akunina [59]

It is 2/5...You plug in -4/5 into x and plug 1/3 into y

4 0

3 years ago

Number of Words in Book Titles: 6, 3, 5, 2, 2, 3, 3, 1,3

3241004551 [841]

Answer:

About 3.11

Step-by-step explanation:

Add the numbers and divide the value by the number of values in the data set.

6 + 3 + 5 + 2 + 2 + 3 + 3 + 1 + 3 = 28

28/9 = 3.1111...

3.111... ≈ 3.11

Hope this helps.

8 0

4 years ago

A bookstore contains 75972 books,divided in to three sections. The science represents 1/3 of the total books. The remaining book

S_A_V [24]

Answer:

12,662 books

Step-by-step explanation:

Total number of books = 75,972

No. of science books = ⅓ of 75,972 = ⅓*75,972 = 25,324 books.

No. of business books = 75% of the remaining books = 75% of (75,972 - 25,324)

= $\frac{75}{100}*50,648 = 37,986$

No. of business books = 37,986

No. of maths books in the math section = 75,972 - (25,324 + 37,986)

= 75,972 - 63,310

= 12,662 books

7 0

4 years ago

What is the surface area of a prism with height of 11 width of 5 and length of 12

Nesterboy [21]

Answer:

474

Step-by-step explanation:

formula =ph+2B

p=perimeter of base = 34

h=height=11

B=base area =60

(34×11)+2(60)

8 0

3 years ago

Expand 3(2y+1) Answer this, please.