Paul: 140 + 12x
Jacklyn: 56 + 16x
Where x is how many practice sessions he had this season
"After how many more practices will Paul and Jacklyn have completed the same number of laps?"
This means what will x be if both equations are equal to each other
140 + 12x = 56 + 16x
Isolate x in one side by subtracting both sides by 12x
140 + 12x - 12x = 56 + 16x - 12x
140 = 56 + 4x
Subtract both sides by 56 to shift the 56 from the right side to the left side
140 - 56 = 56 - 56 + 4x
84 = 4x
Divide both sides by 4 to isolate x
84/4 = 4/4x
21 = x
x = 21
They'll have completed the same number of laps after 21 practices
Hope it helps :)
Branliest would be appreciated
Answer:
4g-124= -104, g-12= -7
Step-by-step explanation:
g=5
4g-124= ? g-12
4(5)-124 5-12
4(5)= 20 5-12= -7
20 - 124= -104
Answer:
The number of cars passing or the people arriving during lunch hour will be around 220
Step-by-step explanation:
First we find the for ten minutes period from given data:
Average Cars in 10 minutes = (18+38+87+16+56+5)/6
Average Cars minutes = 36.67
Now, for average cars in 1 hr, we must multiply this value by 6. As, 10 minutes multiplied by 6 equals 1 hr.
Average cars in an hour = 36.67*6
<u>Average Cars in an hour = 220</u>
Hence, the number of cars or people arriving during lunch hour will also be equal to average number of cars arriving during an hour.
20? I’m not for sure maybe look in the book? That’s the answer I got and it was right
