Part a: 32/60=8/15
part b: 30/60=1/2
Answer:
D = 300 m
Step-by-step explanation:
<u><em>Given :</em></u>
Speed = 5 m/s
Time = 1 min = 60 secs
<u><em>Required:</em></u>
Distance = ?
<u><em>Formula :</em></u>
Speed = Distance/Time
<u><em>Solution:</em></u>
Distance = Speed × Time
D = 5 × 60
D = 300 m
Answer:
Option c. 81/2
Step-by-step explanation:
Fifth term: a5=?
First term: a1=8
Common ratio: r=3/2
an=a1*r^(n-1)
with n=5
a5=a1*r^(5-1)
a5=a1*r^4
Replacing the known values:
a5=8*(3/2)^4
a5=8*(3)^4/(2)^4
a5=8*81/16
Simplifying: Dividing the numerator and denominator by 8:
a5=(8*81/8)/(16/8)
a5=81/2
Answer: Option c. 81/2
I think your asking how much the school will have left over. If so:
125 ( not including the tickets)
It depends on how many kids are coming to the dance in order to fully solve this problem.
You didn't word this properly so that what I got with what I had:)
If you have anymore questions, ask me them on my profile so I'll be sure to get them:)
I hope this helps:)
4n 5 + 3.5n 5 - 2.1n 5 = n 5 (4 + 3.5 - 2.1) = n 5 * 5.4 = 5.4n 5
