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julia-pushkina [17]
3 years ago
12

Prove that lines 3x-4y=12 and 3y=12-4x are perpendicular.

Mathematics
1 answer:
Svetllana [295]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

If 2 lines are perpendicular then the product of their slopes equals - 1

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Consider the given equations

3x - 4y = 12 ( subtract 3x from both sides )

- 4y = - 3x + 12 ( divide terms by - 4 )

y = \frac{3}{4} x - 3 ← in slope- intercept form

with slope m = \frac{3}{4}

3y = 12 - 4x = - 4x + 12 ( divide terms by 3 )

y = - \frac{4}{3} x + 4 ← in slope- intercept form

with slope m = - \frac{4}{3}

Then

\frac{3}{4} × - \frac{4}{3} = - 1

Since the product of their slopes = - 1 then the lines are perpendicular

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