The answer is true as it will change on its own
Answer:
def printInfo(some_dict):
print(len(some_dict['locations']), "LOCATIONS")
for location in some_dict['locations']:
print(location)
print()
print(len(some_dict['instructors']), "INSTRUCTORS")
for location in some_dict['instructors']:
print(location)
seattle = {
'locations': ['San Jose', 'Seattle', 'Dallas', 'Chicago', 'Tulsa', 'DC', 'Burbank'],
'instructors': ['Michael', 'Amy', 'Eduardo', 'Josh', 'Graham', 'Patrick', 'Minh', 'Devon']
}
printInfo(seattle)
Explanation:
Answer:
from collections import Counter
def anagram(dictionary, query):
newList =[]
for element in dictionary:
for item in query:
word = 0
count = 0
for i in [x for x in item]:
if i in element:
count += 1
if count == len(item):
newList.append(item)
ans = list()
for point in Counter(newList).items():
ans.append(point)
print(ans)
mylist = ['jack', 'run', 'contain', 'reserve','hack','mack', 'cantoneese', 'nurse']
setter = ['ack', 'nur', 'can', 'con', 'reeve', 'serve']
anagram(mylist, setter)
Explanation:
The Counter class is used to create a dictionary that counts the number of anagrams in the created list 'newList' and then the counter is looped through to append the items (tuple of key and value pairs) to the 'ans' list which is printed as output.
