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Crank
3 years ago
13

The price of all rail season tickets increased by 6%. After the increase, the price of a rail season ticket from Sheffield to Le

eds was £2883.20
Work out the price before this increase.

please show step by step answer ​
Mathematics
1 answer:
valentina_108 [34]3 years ago
8 0

Answer:

£2720

Step-by-step explanation:

106%=2883.20

100%=x

106x=288320

divide both by 106 it gives 2720

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Quit smoking: In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.
Flauer [41]

Answer:

The p-value of the test is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

Step-by-step explanation:

Test if less than half of HIV-positive smokers have used a nicotine patch:

At the null hypothesis, we test if the proportion is of at least half, that is:

H_0: p \geq 0.5

At the alternative hypothesis, we test if the proportion is below 0.5, that is:

H_1: p < 0.5

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that \mu = 0.5, \sigma = \sqrt{0.5*(1-0.5)} = 0.5

In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.

This means that n = 444, X = \frac{202}{444} = 0.455

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.455 - 0.5}{\frac{0.5}{\sqrt{444}}}

z = -1.9

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.455, which is the p-value of z = -1.9.

Looking at the z-table, z = -1.9 has a p-value of 0.0287.

The p-value is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

5 0
3 years ago
X over 3 - 2 = 5x - 2 , having trouble solving for x or x/3 -2 = 5x -2
Len [333]
I got x=0 because I simplified both sides of the equation and then isolated the equation
7 0
3 years ago
Austin takes 1 minute and 45 seconds to run three-quarters of a circular track. His rate of motion is /
castortr0y [4]
Length of circular track is:

L = 2*r*pi

He run 3/4 of it so length is:
L' = 3*2/4*r*pi = 3/2*r*pi

To calculate speed of his movement we use formula:
v = s/t where s = L' and t = 1 minute 45 seconds = 105 seconds

v = L'/t = 3*r*pi/2*105

v = r* pi/70

If we take that r = 1
 
answer
\pi /70
6 0
3 years ago
Given f(x)=-1/7√16-x^2 find f^-1(x)
Vera_Pavlovna [14]

Answer:

f^{-1}(x)=\pm \sqrt{49x^2-16}

Not a function.

Step-by-step explanation:

The given function is;

f(x)=-\frac{1}{7}\sqrt{16-x^2}

Let y=-\frac{1}{7}\sqrt{16-x^2}

Interchange x and y;

x=-\frac{1}{7}\sqrt{16-y^2}

Solve for y;

-7x=\sqrt{16-y^2}

Square both sides

(-7x)^2=(\sqrt{16-y^2})^2

49x^2^2=16-y^2

49x^2^2-16=y^2

y=\pm \sqrt{49x^2-16}

The inverse is

f^{-1}(x)=\pm \sqrt{49x^2-16}

f^{-1}(x)=\pm \sqrt{49x^2-16} is not a function because one x-value maps onto to different y-values.

6 0
3 years ago
What is the average rate of change of f(x) = 5x – 7 from x = -3 to x = 7?
hram777 [196]

Answer:

f(x) = 5x - 7 \\ change = f(7) - f( - 3) \\  = ((5)(7) - 7) - ((5)( - 3) - 7) \\  = (35 - 7) - ( - 15 - 7) \\  = (28) - ( - 22) \\  = 50 \\ average \: change =  \frac{change}{2}  \\  =  \frac{50}{2}  \\  = 25

3 0
3 years ago
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