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vodka [1.7K]
2 years ago
15

Name The operation you do first. 4+ (3)(-8)+7

Mathematics
1 answer:
oee [108]2 years ago
3 0

Answer:

you would do the parentheses first, in PEMDAS, parentheses come first

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For a set S of numbers, a member c of S is called the maximum of S if and only if c is an upper bound of S . Prove that S has a
victus00 [196]

Answer:

See proof below

Step-by-step explanation:

Remember, an upper bound of an ordered set A is an element u∈A such that u≥a for all a∈A. A is bounded above when A has an upper bound. The supremum of A exists when A is bounded above (careful, this is only true for subsets of real numbers!). It is the least upper bound of A, that is, supA≤u for all upper bounds of A, u.

Since we want to prove an "if and only if" statement, we have to prove the following to implications:

First, asume that S has a maximum. Denote it by M. Then M is an upper bound of S, thus supS exists and M≤supS. However, M∈S thus, by definition of upper bound, supS≤M. Combining these inequalities, M=supS, thus S is bounded above and M=supS∈S.

For the second implication, assume that S is bounded from above and sup S belongs to S. supS is an upper bound, and by assumption, supS∈S. Then, according to your definition, supS is the maximum of S, hence S has a maximum.

This proves the statement.  

4 0
3 years ago
4. Professor Kingsfield's class follows very strict grading guidelines. Assume that student averages in Kingsfield's class are n
gtnhenbr [62]

<em>Answer:</em>

<em>For grade A ,a student needs Z score of 2 or above, the required score is</em>

<em> X = 68 + 12Z =92, For grade B, a student needs Z score between 1 and 2 . </em>

<em> The required score is = 68 + (12 * 1) < X = 68 + ( 12 * 2) = 80 < X < 92, For grade C ,a student needs Z score between -1 and 1 . The  required score is = 68 + ( 12 * x - 1) < X = 68 + (12 * x 1) = 56 <X<80. For the  grade D, a student needs Z score between -2 and -1 . </em>

<em> The required score is = 68 + (12 * x -2) < X = 68 + (12 * x -1) = 44< X< 56</em>

Step-by-step explanation:

<em>From the given question, </em>

<em>let the rv X represent student's score.</em>

<em>Z = x - 68/12  ~ N (0,1 )</em>

<em>Now, we know for a standard normal distribution</em>

<em>Thus,</em>

<em>For grade A ,a student needs Z score of 2 or above, the required score is</em>

<em> X = 68 + 12Z =92</em>

<em>For grade B, a student needs Z score between 1 and 2 . </em>

<em> The required score is = 68 + (12 * 1) < X = 68 + ( 12 * 2) = 80 < X < 92</em>

<em>For grade C ,a student needs Z score between -1 and 1 . </em>

<em> The  required score is = 68 + ( 12 * x - 1) < X = 68 + (12 * x 1) = 56 <X<80</em>

<em>For the  grade D, a student needs Z score between -2 and -1 . </em>

<em> The required score is = 68 + (12 * x -2) < X = 68 + (12 * x -1) = 44< X< 56</em>

<em>For student  with score less 44 gets an F.</em>

<em>Note: find an attached image for the graphic sketch of the normal distribution.</em>

3 0
3 years ago
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