Answer:
Therefore the height of the tower is 116.75 m.
Step-by-step explanation:
Given that a pole that is 2.6 m tall casts a shadow that is 1.03 m long.
Here the height of a object directly proportional to the shadow. It means
Height of the object ∝ shadow
Height of the object= k.shadow
[k is the proportional constant.]
[Height of object is denoted by h and shadow is denoted by s]
Then,
[h₁ is the height of the pole and s₁is the length of the shadow]
Again for the tower
[h₂ is the height of the tower and s₂ is the length of the shadow]
Therefore,
![\frac{h_1}{s_1}=\frac{h_2}{s_2} =k](https://tex.z-dn.net/?f=%5Cfrac%7Bh_1%7D%7Bs_1%7D%3D%5Cfrac%7Bh_2%7D%7Bs_2%7D%20%3Dk)
............(1)
Given
,
and
Putting the value of
and
equation (1)
![\frac{2.6}{1.03}=\frac{h_2}{46.25}](https://tex.z-dn.net/?f=%5Cfrac%7B2.6%7D%7B1.03%7D%3D%5Cfrac%7Bh_2%7D%7B46.25%7D)
[cross multiplication]
![\Rightarrow h_2 = \frac{2.6\times 46.25}{1.03}](https://tex.z-dn.net/?f=%5CRightarrow%20h_2%20%3D%20%5Cfrac%7B2.6%5Ctimes%2046.25%7D%7B1.03%7D)
![\Rightarrow h_2= 116.75](https://tex.z-dn.net/?f=%5CRightarrow%20h_2%3D%20116.75)
Therefore the height of the tower is 116.75 m.
Answer:
Step-by-step explanation: 5x-5=3x+13---> 5x-3x=13+5---> 2x=13+5---- 2x=18----> x=9 hope it helps
You don’t have to worry about the t subtract 3 and 9
Answer:
T=5
Step-by-step explanation:
4t+90=110
4t=20
t=5