The value of L4 and R4 over [0,7] for the function f(x) = 6x² will be 2[2√0 + 2√2 + 2√4 + 2√6] and 2[2√2 + 2√4 + 2√6 + 2√8] respectively.
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
It is given that the function is,
I'm assuming that you mean the left and right Riemann sums with four equal subintervals when you refer to L4 and R4.
If so, then Δx = (8-0)/4 = 2, and f(x) = 2√x.
L4 = f(0)Δx + f(2)Δx + f(4)Δx + f(6)Δx
L4 =2[2√0 + 2√2 + 2√4 + 2√6]
R4 = 2[2√2 + 2√4 + 2√6 + 2√8]
Thus, the value of L4 and R4 over [0,7] for the function f(x) = 6x² will be 2[2√0 + 2√2 + 2√4 + 2√6] and 2[2√2 + 2√4 + 2√6 + 2√8] respectively.
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if you have 2,424.13 the first number 2 represents 20 and the second represents the number 2,000
Answer:
A. right 2, up 3
Step-by-step explanation:
We have that,
The function is transformed to .
We see that,
The function f(x) is translated 2 units to the right and 3 units upwards to obtain the function g(x).
So, the correct transformation is 'right 2, up 3'.
option A is correct.
To determine the final score of Tanya, we simply add the product of the percentages given with the score she gained in those category. That is,
Tanya's score = (0.80)(86) + (0.2)(93)
Tanya's score = 87.4
Therefore, Tanya's final score is 87.4%.
Answer:
<u>It would be the fourth option</u>
Step-by-step explanation:
If you try this for each pair, it is true
2/2 = 1 1 + 4 = 5
3/2 = 1.5 1.5 +4 = 5.5
4/2 = 2 2 + 4 = 6
6/2 = 3 3 + 4 = 7