Answer:
The word problem is "How many $25 are there in $125?"
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Step-by-step explanation:
Given
Required
Write a word problem for the expression
We start by solving the given equation
Divide both sides by $25
This implies that there are 5, $25 in $125
<em>Hence; The word problem is "How many $25 are there in $125?"</em>
Complete question is;
The function f(x) = (25000 + 280x)/x models the average cost per unit, f(x), for Electrostuff to manufacture x units of Electrogadget IV. How many units must the company produce to have an average cost per unit of $390?
Answer:
227 units
Step-by-step explanation:
We are given the function;
f(x) = (25000 + 280x)/x
Where;
f(x) is the average cost per unit
x is the number of units
Now, we want to find out how many units the company must produce to have an average cost per unit of $390.
Thus, plugging $390 for f(x), we have;
390 = (25000 + 280x)/x
When we cross multiply, we get;
390x = 25000 + 280x
390x - 280x = 25000
110x = 25000
x = 25000/110
x ≈ 227
Answer:
Step-by-step explanation:
Given
- A is between C and T
- CA =4x + 6
- AT =7x-6
- CT =132
As per segment addition postulate:
- CT = CA + AT
- 4x + 6 + 7x - 6 = 132
- 11x = 132
- x = 132/11
- x = 12
Answer: 2000
Step-by-step explanation:
55 multiplied by 20
is equal to 1,100
100 multiplied by 20
is equal to 2000
2000 ppl were surveyed
