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natali 33 [55]
3 years ago
11

Matt Miller, age 28, takes out $50,000 of straight-life insurance. His annual premium is $418.20. Using

Mathematics
1 answer:
Citrus2011 [14]3 years ago
3 0
Look at the table that mentions "cash value". Locate "20" in the first column (the "years" column). Right next to 20 is the value 265. That's the multiplier we will use. 

50,000/1,000 = 50 will be multiplied with 265 to get 265*50 = 13,250

So the cash value of this policy is $13,250
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Marina86 [1]
12+(3e) that’s at least what i think.
6 0
3 years ago
Let p=x^2+6
stepan [7]
That's a bit of a nasty. Where ever you see (x^2 + 6) you put in p.
p^2  - 21 = 4(x^2 + 6)
p^2 - 21 = 4p
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A <<<< answer. 

8 0
4 years ago
On a test hailey answered 64 out of 75 questions correctly. What percent of her answers were correct? With the work please!!
Airida [17]
Set up a proportion

64/75= x/100

Cross multiply:
64*100=6400
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Final answer: 85.333...%
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3 years ago
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alexgriva [62]

Answer:

Option A

Step-by-step explanation:

   We know that the "3x ? 2" line must be positive, so it cannot be C or D. The other line is negative, so the "2x ? 5" line must be -2x. This gets rid of option B, leaving us with our answer of A!

Have a nice day!

    I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

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5 0
3 years ago
A function of random variables used to estimate a parameter of a distribution is a/an _____.
stiks02 [169]

A function of random variables utilized to calculate a parameter of distribution exists as an unbiased estimator.

<h3>What are the parameters of a random variable?</h3>

A function of random variables utilized to calculate a parameter of distribution exists as an unbiased estimator.

An unbiased estimator exists in which the difference between the estimator and the population parameter grows smaller as the sample size grows larger. This simply indicates that an unbiased estimator catches the true population value of the parameter on average, this exists because the mean of its sampling distribution exists the truth.

Also, we comprehend that the bias of an estimator (b) that estimates a parameter (p) exists given by; E(b) - p

Therefore, an unbiased estimator exists as an estimator that contains an expected value that exists equivalent to the parameter i.e the value of its bias exists equivalent to zero.

Generally, in statistical analysis, the sample mean exists as an unbiased estimator of the population mean while the sample variance exists as an unbiased estimator of the population variance.

Therefore, the correct answer is an unbiased estimator.

To learn more about unbiased estimators refer to:

brainly.com/question/22777338

#SPJ4

4 0
1 year ago
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