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3 years ago

If 12m=5n, then m/n=?

Mathematics

1 answer:

nignag [31]3 years ago

4 0

Answer:

$\frac{m}{n}=\frac{5}{12}$

Step-by-step explanation:

Given:

$12m=5n$

Dividing both sides b 'n'

$12*\frac{m}{n}=5$

So,

$\frac{m}{n}=\frac{5}{12}$

The ratio of 'm' and 'n' is 5:12

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each of the four sides of a swimming pool measures 12 meters who is 6 m in feet how much water is needed to fit in completely

Snezhnost [94]

Volume = Length x Width x Height

Volume = 12 x 12 x 6 = 864 m³

Answer: 864 m³

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4 years ago

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Which is the graph of y ≤ 1 – 3x?

34kurt

It’s the first one because when you have a line under the inequality it’s always going to be a solid line and since it’s negative it’s shaded below.

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3 years ago

Please help it’s urgent this assignment is almost due!!!?

Advocard [28]

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2 years ago

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How much does 4 5/7 kg of candy cost if 5/6 kg costs $7.50

Aliun [14]

Answer:

It costs $42.43

Step-by-step explanation:

Lets explain how to solve the problem

- The cost of $\frac{5}{6}$ kilogram of candy is $7.5

- We need to find the cost of $4\frac{5}{7}$ kilogram

We can use the ratio to find the answer

======= Dollar : Kilogram

======= 7.5 : $\frac{5}{6}$

======= c : $4\frac{5}{7}$

By using cross multiplication

∴ c × $\frac{5}{6}$ = 7.5 × $4\frac{5}{7}$

∵ $4\frac{5}{7}$ = $\frac{4*7+5}{7}$

∴ $4\frac{5}{7}$ = $\frac{33}{7}$

∴ c × $\frac{5}{6}$ = 7.5 × $\frac{33}{7}$

∴ c × $\frac{5}{6}$ = $\frac{495}{14}$

Divide both sides by $\frac{5}{6}$

∴ c = $\frac{495}{14}$ ÷ $\frac{5}{6}$

Change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∴ c = $\frac{495}{14}$ × $\frac{6}{5}$

∴ c = $\frac{297}{7}$ = 42.43 dollars

∵ c represents the cost of $4\frac{5}{7}$ kg

∴ It costs $42.43

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4 years ago

Suppose that (x, -8/17) is a point in quadrant IV lying on the unit circle.

AlladinOne [14]

Since the point lies on the unit circle, it satisfies

$x^2+\left(-\dfrac8{17}\right)^2=x^2+\left(\dfrac8{17}\right)^2=1$

Solving for $x$ gives two possible solutions:

$x^2=1-\left(\dfrac8{17}\right)^2$
$x=\pm\sqrt{1-\left(\dfrac8{17}\right)^2}$

Given that $x$ is in quadrant IV, you know that its value must be positive, so

$x=\sqrt{1-\left(\dfrac8{17}\right)^2}=\sqrt{\dfrac{225}{289}}$

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3 years ago