Answer:
7
4
Step-by-step explanation:
The <u>actual values</u> are shown on the given graph as <u>blue points</u>.
The <u>line of regression</u> is shown on the given graph as the <u>red line</u>.
From inspection of the graph, in the year 2000 the actual rainfall was 43 cm, shown by point (2000, 43). It appears that the regression line is at y = 50 when x is the year 2000.
⇒ Difference = 50 - 43 = 7 cm
<u>In 2000, the actual rainfall was </u><u>7</u><u> centimeters below what the model predicts</u>.
From inspection of the graph, in the year 2003 the actual rainfall was 44 cm, shown by point (2003, 40). It appears that the regression line is at y = 40 when x is the year 2003.
⇒ Difference = 44 - 40 = 4 cm
<u>In 2003, the actual rainfall was </u><u>4</u><u> centimeters above what the model predicts.</u>
28.50x + 110.99(14-x)=811.45
distribute
28.50 x + 1553.86-110.99x =811.45
combine like terms
-82.49x+1553.86=811.45
subtract 1553.86 from each side
-82.49x =-742.41
divide by -82.49
x=9
He bought 9 of the 28.50 features and 5 of the 110.99 features
1134.11
This should be the answer
x = 1/120
i did not see the comment about the 1/5 until now
hope this helps