More than 2 ... there is a right and a obtuse i think
Answer:

Step-by-step explanation:
To solve this problem we need to write the mixed fraction as a fractional number, as follows:


Then, evaluating the expression:
×
= 
→ 
Answer:
Given: y = x2 + 4x – 5
Find the following
y-intercept
x-intercepts or the zeros of the functions or roots
graph of the function, given vertex is at (-2, -9)
Solve the system of linear equations – x + 6y = 8 2x + 5y = 3
Write the names of curves, given their equations:
x2/16 + y2/9 = 1
3y = 2x + 5
(x - 5)2 + (y + 6)2 = 25
x2/16 – y2/25 = 1
y = 2x2 + 10x + 25
Write down the first five terms of the arithmetic progression with the first term 8 and common difference 7, then find the 17th
Write down the first five terms of the geometric progression with the first term 3 and common ratio 2, then find the 17th
Answer:
0
Step-by-step explanation:
73x=0
Let's allow ?=x because we need an unknown number.
x=0/73=0
x=0
Answer:
Comparing means from dependent samples.
Step-by-step explanation:
In the scenario described above, the 25 sampled individuals were used to test the effect of weightlifting on alleviating back pain. The samples used were not changed nor altered during the study as the same subjects who were tested to measure their level of pain before lifting weight were the same group subjected to the actual weight lifting test and again had their level of pain tested. Since only one group was involved in the study ( a single group was tested on neutral and actual treatment). Hence, the study used dependent samples to compare the average level of pain.