All categories

2 years ago

Shape 2 (2.5,-0.5) , (4,-1.5) , (2.5,-2) , (2.5,-.5)

Mathematics

2 answers:

sveta [45]2 years ago

3 0

Answer:

yes what the question

Step-by-step explanation:

Elenna [48]2 years ago

3 0

It's a triangle!! btw good luck on the rest of ur work

You might be interested in

What is the area of the trapezoid with height 10 units?

Ainat [17]

Ya but I think its like 40 hope this helps

5 0

3 years ago

Read 2 more answers

30.28 kg of beef were placed into 24 packages of equal weight. What is the weight of one package of beef? Please show your work.

klemol [59]

Answer:

1.26kg per package

Step-by-step explanation:

30.28/24= 1.2616...

5 0

3 years ago

Write each mixed as a decimal. a) 1 3/4 b) 2 13/20

kakasveta [241]

Answer:

a. 1.75

b. 2.65

those are as a decimal

6 0

3 years ago

A tailor pays $10.25 per yard for wool and pays $5.75 per yard for cotton. He bought 4.8 yards of cotton and spent a total of $8

Alex777 [14]

Answer:

cotton and wool

Step-by-step explanation:

7 0

3 years ago

A. f(x) = l-2xl - 3 Domain: {1, 2, 3} Find the range

gizmo_the_mogwai [7]

Hello there!

We are given the function:

$\displaystyle \large{ f(x) = | - 2x| - 3} \\$

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

x = 1

$\displaystyle \large{ f(1) = | - 2(1)| - 3} \\ \displaystyle \large{ f(1) = | - 2| - 3} \\$

Recall that any numbers in absolute value are always positive.

$\displaystyle \large{ f(1) = 2 - 3} \\ \displaystyle \large{ f(1) = - 1} \\$

x = 2

$\displaystyle \large{ f(2) = | - 2(2)| - 3} \\ \displaystyle \large{ f(2) = | - 4 | - 3} \\ \displaystyle \large{ f(2) = 4 - 3} \\ \displaystyle \large{ f(2) = 1}$

x = 3

$\displaystyle \large{ f(3) = | - 2(3)| - 3} \\ \displaystyle \large{ f(3) = | - 6| - 3} \\ \displaystyle \large{ f(3) = 6 - 3} \\ \displaystyle \large{ f(3) = 3}$

Therefore, Range: {-1,1,3}

Let me know if you have any questions!

Topic: Absolute Value Function / Modulus Function

6 0

3 years ago