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attashe74 [19]
2 years ago
12

the standard deviation is a better measure of risk than the coefficient of variation if the expected returns of the securities b

eing compared differ significantly.
Business
1 answer:
IgorC [24]2 years ago
6 0

Answer:

False

Explanation:

You might be interested in
In mixed economies, governments also tend to take into state ownership troubled firms whose continued operation is thought to be
Archy [21]

This is true. If a firm is considered to be of national interest (i.e. defense or national security), in a mixed economy, the government can take control of the failing business.

3 0
2 years ago
Oval Inc. just paid a dividend equal to $1.50 per share on its common stock, and it expects this dividend to grow by 4 percent p
Rainbow [258]

Answer:

e. 14.60%

Explanation:

The computation of Oval's cost of new common equity is shown below:-

Price of stock = Estimated dividends for next period ÷ (Required rate of return - Growth rate)

Dividend =  $1.50 × (1 + 4%)

= $1.56

Price of stock would be the price net of flotation cost

= $16 × (1 - 8%)

= $14.72

Required rate of return

= (1.56 ÷ 14.72) + 0.04

= 14.60%

8 0
3 years ago
On January 1, Year 1, Sayers Company issued $280,000 of five-year, 6 percent bonds at 102. Interest is payable semiannually on J
mel-nik [20]

Answer:

The cash received from bond issuance is journalized as follows:

Dr Cash                                $285,600

Cr  Bonds payable                                  $280,000

Cr Premium on Bonds payable                   $5,600

The June 30 and 31 December Year 1 interest on the bonds are recorded thus:

30 June

Dr Interest expense(bal fig) $7,840                                          

Dr Premium on bonds           $560

Cr Cash                                         $8400

31 December

Dr Interest expense(bal fig) $7,840                                          

Dr Premium on bonds           $560

Cr Cash                                         $8400

The June 30 and 31 December Year 2 interest on the bonds are recorded thus:

30 June

Dr Interest expense(bal fig) $7,840                                          

Dr Premium on bonds           $560

Cr Cash                                             $8400

31 December

Dr Interest expense(bal fig) $7,840                                          

Dr Premium on bonds           $560

Cr Cash                                            $8400

Explanation:

The amount realized from the bond is calculated thus:

$280,000*102%=$285,600

Premium on  bond=Bonds proceeds-par value

                                =$285,600-$280,000

                                =$5,600

Semi-annual amortization of bond premium=$5,600/5*6/12

                                                                         =$560

Semi-annual interest payment=$280,000*6%*6/12

                                                 =$8,400

5 0
3 years ago
Suppose that output (Y ) in an economy is given by the following aggregate production function: Yt = Kt + Nt where Kt is capital
shusha [124]

Answer:

Check the explanation

Explanation:

Yt = Kt + Nt

Taking output per worker, we divide by Nt

Yt/Nt = Kt/Nt + 1

yt = kt + 1

where yt is output per worker and kt is capital per worker.

a) With population being constant, savings rate s and depreciation rate δ.

ΔKt = It - δKt

dividing by Nt, we get

ΔKt/Nt = It/Nt - δKt/Nt ..... [1]

for kt = Kt/Nt, taking derivative

d(kt)/dt = d(Kt/Nt)/dt ... since Nt is a constant, we have

d(kt)/dt = d(Kt/Nt)/dt = (dKt/dt)/Nt = ΔKt/Nt = It/Nt - δKt/Nt = it - δkt

thus, Capital accumulation Δkt = i – δkt

In steady state, Δkt = 0

That is I – δkt = 0

S = I means that I = s.yt

Thus, s.yt – δkt = 0

Then kt* = s/δ(yt) = s(kt+1)/(δ )

kt*= skt/(δ) + s/(δ)

kt* - skt*/(δ) = s/(δ)

kt*(1- s/(δ) = s/(δ)

kt*((δ - s)/(δ) = s/(δ)

kt*(δ-s)) = s

kt* = s/(δ -s)

capital per worker is given by kt*

b) with population growth rate of n,

d(kt)/dt = d(Kt/Nt)/dt =

= \frac{\frac{dKt}{dt}Nt - \frac{dNt}{dt}Kt}{N^{2}t}

= \frac{dKt/dt}{Nt} - \frac{dNt/dt}{Nt}.\frac{Kt}{Nt}

= ΔKt/Nt - n.kt

because (dNt/dt)/Nt = growth rate of population = n and Kt/Nt = kt (capital per worker)

so, d(kt)/dt = ΔKt/Nt - n.kt

Δkt = ΔKt/Nt - n.kt = It/Nt - δKt/Nt - n.kt ......(from [1])

Δkt = it - δkt - n.kt

at steady state Δkt = it - δkt - n.kt = 0

s.yt - (δ + n)kt = 0........... since it = s.yt

kt* = s.yt/(δ + n) =s(kt+1)/(δ + n)

kt*= skt/(δ + n) + s/(δ + n)

kt* - skt*/(δ + n) = s/(δ + n)

kt*(1- s/(δ + n)) = s/(δ + n)

kt*((δ + n - s)/(δ + n)) = s/(δ + n)

kt*(δ + n -s)) = s

kt* = s/(δ + n -s)

.... is the steady state level of capital per worker with population growth rate of n.

3. a) capital per worker. in steady state Δkt = 0 therefore, growth rate of kt is zero

b) output per worker, yt = kt + 1

g(yt) = g(kt) = 0

since capital per worker is not growing, output per worker also does not grow.

c)capital.

kt* = s/(δ + n -s)

Kt*/Nt = s/(δ + n -s)

Kt* = sNt/(δ + n -s)

taking derivative with respect to t.

d(Kt*)/dt = s/(δ + n -s). dNt/dt

(dNt/dt)/N =n (population growth rate)

so dNt/dt = n.Nt

d(Kt*)/dt = s/(δ + n -s).n.Nt

dividing by Kt*

(d(Kt*)/dt)/Kt* = s/(δ + n -s).n.Nt/Kt* = sn/(δ + n -s). (Nt/Kt)

\frac{sn}{\delta +n-s}.\frac{Nt}{Kt}

using K/N = k

\frac{s}{\delta +n-s}.\frac{n}{kt}

plugging the value of kt*

\frac{sn}{\delta +n-s}.\frac{(\delta + n -s)}{s}

n

thus, Capital K grows at rate n

d) Yt = Kt + Nt

dYt/dt = dKt/dt + dNt/dt = s/(δ + n -s).n.Nt + n.Nt

using d(Kt*)/dt = s/(δ + n -s).n.Nt from previous part and that (dNt/dt)/N =n

dYt/dt = n.Nt(s/(δ + n -s) + 1) = n.Nt(s+ δ + n -s)/(δ + n -s) = n.Nt((δ + n)/(δ + n -s)

dYt/dt = n.Nt((δ + n)/(δ + n -s)

dividing by Yt

g(Yt) = n.(δ + n)/(δ + n -s).Nt/Yt

since Yt/Nt = yt

g(Yt) = n.(δ + n)/(δ + n -s) (1/yt)

at kt* = s/(δ + n -s), yt* = kt* + 1

so yt* = s/(δ + n -s) + 1 = (s + δ + n -s)/(δ + n -s) = (δ + n)/(δ + n -s)

thus, g(Yt) = n.(δ + n)/(δ + n -s) (1/yt) =  n.(δ + n)/(δ + n -s) ((δ + n -s)/(δ + n)) = n

therefore, in steady state Yt grows at rate n.

5 0
3 years ago
"If the option will cost the investor an additional $10,000, should the investor purchase the option? Enter your answer in thous
kykrilka [37]

Answer:

“Should” or “should not” depend on the cost rate of the option and the risk appetite of investors.

Explanation:

An option is a contract that allows investors to buy or sell instruments such as security, Exchanged Traded Fund or an index at a pre-determined price over a certain period of time.

If the option will cost the investor an additional $10,000 and it is the cost for an option of $10 million investment, then it cost only 0.1% additionally, but it can secure the position of this investment; then the investor should buy this option.

Vice versa, if the additional $10,000 is much more than expected profit, and even lower but significantly drop down the total profit of an investment; and the investor always wish to have a high profit regardless high risk; then he shouldn’t buy this option.

6 0
2 years ago
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