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N76 [4]
2 years ago
15

Someone pls help me I will make you Brainly

Mathematics
1 answer:
AURORKA [14]2 years ago
8 0

Answer:

it should be step 2

Step-by-step explanation:

You might be interested in
Simplify the expression below: 4+2×[(3+1)×5] (show work please need it for review)
____ [38]

Answer:

44

Step-by-step explanation:

Parenthesis

Exponents

Multiply

Divide

Add

Subtract

First we need to do the work inside the parenthesis that are in the boxed parenthesis

3 + 1 = 4

4 * 5 = 20

Now we multiply

20 * 2 = 40

Now we add

40 + 4 = 44

Best Of Luck,

- I.A. -

5 0
3 years ago
How to solve by completing the square
AveGali [126]

https://www.mesacc.edu/~scotz47781/mat120/notes/quad_formula/quad_formula.html

Use this link to help you .

6 0
3 years ago
URGENT! (Grades close tomorrow and turning this in will boost my grade from a B to an A in College Algebra. I can't figure these
zvonat [6]

Answer:

  24.  see below for a drawing with axis intercepts labeled

  30.  the plane is parallel to the y-z plane. It is "x=4". The only axis intercept is (4, 0, 0).

Step-by-step explanation:

24. The axis intercepts are fairly easily found. You can do it a couple of ways.

<u>first way</u>

  • Set other variables to zero and divide by the coefficient of the variable of interest.

For 3x +5y +15z = 15, the x-intercept can be found by setting y and z to zero. This gives ...

  3x = 15

so, dividing by 3 tells you the x-intercept is ...

  x = 15/3 = 5

Likewise, the y- and z-intercepts are, respectively, ...

  y = 15/5 = 3

  z = 15/15 = 1

So, the points where the plane crosses the axes are ...

  (5, 0, 0), (0, 3, 0), (0, 0, 1) . . . . axes intercepts

__

<u>second way</u>

  • Divide by the constant on the right, and express all coefficients as denominators

Doing that gives ...

\dfrac{3x+5y+15z}{15}=1\\\\\dfrac{x}{5}+\dfrac{y}{3}+\dfrac{z}{1}=1

The denominators are the corresponding intercepts. (This is called the "intercept form" of the equation of the plane.)

From the above equation, we see the axis intercepts are ...

  (5, 0, 0), (0, 3, 0), (0, 0, 1) . . . . same as above

Actually, the math for these two methods is virtually identical. The second way does it "all at once", so can take fewer steps. Effectively, you're doing the math of the "first way" and expressing the result in the denominator.

__

Please note that when a variable is missing, there is no intercept for that axis. That is, the plane is parallel to that axis. (In problem 30, for example, the y- and z-variables are missing. The plane x=4 is parallel to the y- and z-axes (the y-z plane).)

_____

In the first attached drawing, the x-axis is red, the y-axis is green, and the z-axis is blue. The labeling of the points is difficult to see, but the axes are a different (lighter) color behind the plane than in front of it. This plane forms a triangle in the first octant (x, y, z > 0).

In the second attached drawing, the x=0 plane is blue; the y=0 plane is green, and the z=0 plane is red. The plane of the equation is yellow. This figure better shows the triangle in the first octant.

3-D graph paper (isometric graph paper) grids are available with a web search. Such might make it easier to draw the planes you need to draw. (See the third attachment for one example.)

3 0
3 years ago
Ben's favorite number is equal to 2 less than 10 times Sam's favorite number. The table shows how the favorite
KengaRu [80]

Answer:

C

Step-by-step explanation:

Hope it helps, Good Luck!!!!

6 0
3 years ago
Use the quadratic formula to solve for x. 4x2 +9x-1=0​
insens350 [35]

Answer:

x=\frac{-9\pm\sqrt{65} }{8}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

Step-by-step explanation:

<u>Step 1: Define</u>

4x² + 9x - 1 = 0

<u>Step 2: Define variables</u>

a = 4

b = 9

c = -1

<u>Step 3: Find roots</u>

  1. Substitute:                    x=\frac{-9\pm\sqrt{9^2-4(4)(-1)} }{2(4)}
  2. Exponents:                   x=\frac{-9\pm\sqrt{81-4(4)(-1)} }{2(4)}
  3. Multiply:                        x=\frac{-9\pm\sqrt{81-16} }{8}
  4. Subtract:                       x=\frac{-9\pm\sqrt{65} }{8}
5 0
2 years ago
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