Question 1:
The answer is angle 4.
Just imagine that both line m and line l are the same line.
Then, just find out which angle matches with what. Angle 1 matches with angle 5. Angle 2 matches with angle 6, and so on.
Thus, angle 8 will match with angle 4.
Question 2:
From what I said about angle 2 and 6 last question, we know that angle 2 and 5 cannot be corresponding.
The answer is alternate interior angles because angles 2 and 5 match the definition for alternate interior angles.
They are not same side interior because then angle 4 would match with angle 2.
They are not alternate exterior because angle 2 and angle 5 are not above line l and below line m (exterior angles).
Have an awesome day! :)
Answer:
Required number is 4.
Step-by-step explanation:
Let the required number be a.
Given,
Sum of ten times the integer and seven times it’s square is 152.
= > Ten times of a + seven times of it's square = 152
= > 10( a ) + 7( a )^2 = 152
= > 10a + 7a^2 - 152 = 0
= > 7a^2 + 10a - 152 = 0
= > 7a^2 + ( 38 - 28 )a - 152 = 0
= > 7a^2 + 38a - 28a - 152 = 0
= > a( 7a + 38 ) - 4( 7a + 38 ) = 0
= > ( a - 4 )( 7a + 38 ) = 0
= > a = 4 or - 38 / 7
Hence the required number is 4.
<span>arithmetic sequence 12,6,0,-6
</span>
<span>
To find 30th term
</span>
<span>
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Answer: 30th term is -162</span>----------------------------------------
Triangles JFE and JLK are similar provided that line segments FE and LK are parallel. This means that corresponding parts of these triangles occur proportionally to one another. In particular,
From this relation we get
Now we can solve for 
:
Answer:
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Step-by-step explanation:
