Answer:
11 am
Step-by-step explanation:
Bus A and Bus B leave the bus depot at 9 am.
Bus A takes 30 minutes to complete its route once
Bus B takes 40 minutes to complete its route once.
We solve this finding the Lowest Common Multiple of the minutes each bus uses to complete it's route
30 = 3 × 10
40 = 4 × 10
= 3 × 4 × 10
= 120 minutes
120 minutes after 9 am is
60 minutes = 1 hour
60 minutes = 1 hour
= 2 hours.
9am + 2 hours
= 11 am.
Therefore, they be back at the bus depot together at 11 am
Answer:
Least to greatest is 81/10, 8 1/9, 8.115 and 9.95
Step-by-step explanation:
Answer:
the answer would be x = 3, 0
Step-by-step explanation:
as much as I would like to, I'm really not that good at explaining things
X/5 - 11 = -13
x/5 - 11 (+11) = -13 (+11)
x/5 = -2
x/5 (5) = -2(5)
x = -10
-10 is your number
hope this helps
All you need to do is put 45 over 100 to make it 45/100, then simplify down until you get your answer. The answer is 9/20 though. There may be better ways, but that's how I do it.
