Answer:
Step-by-step explanation:
We can find this by multiplying the two-thirds of Tanisha's garden by one-fourth, which is 
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I think u just connect the dots
Answer: The hook would be 2.2 inches (approximately) above the top of the frame
Step-by-step explanation: Please refer to the picture attached for further details.
The top of the picture frame has been given as 9 inches and a 10 inch ribbon has been attached in order to hang it on a wall. The ribbon at the point of being hung up would be divided into 5 inches on either side (as shown in the picture). The line from the tip/hook down to the frame would divide the length of the frame into two equal lengths, that is 4.5 inches on either side of the hook. This would effectively give us two similar right angled triangles with sides 5 inches, 4.5 inches and a third side yet unknown. That third side is the distance from the hook to the top of the frame. The distance is calculated by using the Pythagoras theorem which states as follows;
AC^2 = AB^2 + BC^2
Where AC is the hypotenuse (longest side) and AB and BC are the other two sides
5^2 = 4.5^2 + BC^2
25 = 20.25 + BC^2
Subtract 20.25 from both sides of the equation
4.75 = BC^2
Add the square root sign to both sides of the equation
2.1794 = BC
Rounded up to the nearest tenth, the distance from the hook to the top of the frame will be 2.2 inches
<span>The dimensions of the original picture are 12 by 18. Adding the mat of width x around the picture makes the new dimensions of the whole thing (18+2x)(12+2x). Now we need to find x, the width of the mat, in order to then find the new dimensions. We want the largest frame, so we will assume all 80 inches of wood are used.
To find x, notice that the total area - the original picture area = the area of just the wood used. This must equal 80. So let's set up an equation and solve for x.
(18 + 2x) (12 + 2x) - 18 * 12 = 80
216 + 36x + 24x + 4x^2 - 216 = 80
4x^2 + 60x = 80
4x^2 + 60x - 80 = 0
Divide by GCF, which is 4, to simplify the equation:
x^2 + 15x - 20 = 0
Now this can't be factored, so you must either use the quadratic formula or plug it into your graphing calculator and find the x-intercepts.
EIther way the zeros are x = 1.2321, and x = -16.2337
But this is a word problem so we can't have a negative length for x. So the only valid solution for x is 1.2321. This is the width of the mat all around the 12 * 18 picture.
Now let's use x to find the new dimensions:
Remember that the new dimensions are formed by adding 2x (that is, 2 times x, with x being the width of the mat) to the length and width of the original picture.
New width with mat = 12 + 2x = 12 + 2*1.2321 = 14.46 in
New length with mat = 18 + 2x = 18 + 2.1.2321 = 20.46 in</span>
Answer:139 cm squared
Step-by-step explanation:
First separate it:
10x3
7x7
4x15
These are the 3 rectangles that make up this shape
Then multiply
10x3=30
7x7=49
4x15=60
Then add your answers
30+49+60=139cm squared
