Hello,
Answer A
s(x)=3x-7
s(2t-4)=3*(2t-4)-7=6t-12-7=6t-19
Answer: To determine if two lines are parallel or perpendicular, you have to look at the slopes. For the line y=kx+b, k is the slope.
For two lines y=k1x+b1 and y=k2X+b2 ,When K1=K2, two lines are parallel; when K1=-1/k2, two lines are perpendicular. It doesn't matter whatever b1, b2 are. Hence to save time, you only need to calculate k1 and k2.
To calculate the slope k of any line, you have to change the equation to y=kx+b
For -y=3x-2, k=3/(-1)=-3 (you divide -1 on each side of =, but you don't need to calculate -2/(-1))
For -6X+2y=6, K=6/2=3 (you first move the -6x to right side, it becomes 6x, then divide by 2)
Now you can get the answer: The two lines neither parallel nor perpendicular.
Answer:
95
Step-by-step explanation:
Answer:
x=8
Step-by-step explanation:
You would set them equal to each other to get 9x-13=6x+11.
You would them move 6x over so -6x on both sides. This would then get you 3x-13=11.
Then move the -13 over so add 13 to both sides to get 3x=24
Then get x by itself so divide by 3 to get x=24/3.
Then that simplified is 8
The option that is true with regard to the following functions is Option B. "The domain g(x) and h(x) include all real number while the domain of i(x) and h(x) are restricted"
<h3>What is the explanation for the above?</h3>
- Lets examine f(x) = 3x + 14
Note that this function is indicative of a straight-line. See the attached graph for function 1. Note that it doesn't have any end points. That is, it is Asymptote.
- Let us examine h(x) = 3ˣ + 1
This represents an exponential graph. Just like the function above it doesn't have any end point. It however has an asymptote:
y = 0
- Let us look at F'(x) = Log₃ (x = 1).
This is indicative of logarithm graph. It doesn't have any end but has an asymptote x == 0
- Let us take a look at g(x) = X⁴ + 3x² - 14
Notice that in the mid point there is an end point given as (0, -14). Thus, it is correct to state that the function in Option B is the only one that exhibits end behavior and as such is restricted.
Learn more about functions:
brainly.com/question/17043948
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