The correct options are:
A. The scatter plot has an outlier at (15, 2)
B. The scatter plot has a cluster with a range from 2 to 4
<u><em>Explanation</em></u>
Co ordinate of any point can be written in form of (x,y) where first value is the distance across x-axis and second value is the distance across y-axis.
We can see in the plot, that the outlier point is 15 unit across x-axis and then 2 unit across y axis from the origin. So the co ordinate of that point will be (15, 2).
Range means the values across the y-axis. We can see that the cluster starts at y=2 and ends at y=4. That means, the scatter plot has a cluster with a range from 2 to 4.
There are 3 methods to solve this. elimination substitution and graphing but i am going to use the elimination method.
x+2y=17
<u> x-y =2
</u> 0+3y =15 ( subtracted down to eliminate the x)( x-x=0, 2y-(-y)=3y, and 17-2=15)
3y=15 (divide both sides by 3 to solve for y)
y=5
<u>substitute the y=5 in any of the above equations and solve for x
ie... ( </u>meaning where you find y in the equation, u replace it with a 5)
it will be easier to solve for x in (x-y=2) so i will use that one.
x-(5)=2 ( add 5 on both sides to solve for x)
x=7
Answer:
3.4 + 3.4 = 6.8
Step-by-step explanation:
Review your triangle and geometry. Since the triangles are both similar, they would have the same side.. etc.
Answer:
Okay so 5th power of 2 Plus second power of 2 minus 3rd power of 3
