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3 years ago

Please include step by step instruction, so I can learn how to solve the problem. Thank you

Mathematics

1 answer:

Yuki888 [10]3 years ago

7 0

9514 1404 393

Answer:

A, C

Step-by-step explanation:

First of all, recognize that any basic arithmetic operation between a rational number and an irrational number will have an irrational result. That means, you can eliminate any answer choices that involve an irrational number.

Fractions and mixed numbers involving integers are always rational, so you only need to look at the radicals. You know 9 is 3×3, so is a perfect square, and √9 = 3 is rational. You know 5 is not a perfect square, so √5 is irrational.

Considering the above, any expression involving √5 will have an irrational result. That means you can eliminate choices B and D.

choices A and C will result in a rational number

_____

Additional comment

A = 6.8 +0.75 = 7.55 (rational)

C = 6.8 × 0.75 = 5.100 (rational)

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Help,anyone can help me do quetion

a_sh-v [17]

Answer:

B1: x = 51

C1: x = 73, y = 34

Step-by-step explanation:

B1:

By exterior angle theorem:

x° + 54° = 105°

x° = 105° - 54°

x° = 51°

x = 51

x° = 73°(Alternate angles)

x = 73

y° = 34° (corresponding angles)

y = 34

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3 years ago

Using a scale of 1 cm to represent 1 unit, made the

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3 years ago

If you roll two six-faced dice together, you will get 36 possible outcomes. 4 pts 1. List all possible outcomes of the experimen

bezimeni [28]

Given:

Two dice are rolled together.

Total number of possible outcomes.

To find:

The list of total possible outcomes.

The probability of getting a sum of 11 in these outcomes.

The probability of getting a sum less than or equal to 4.

The probability of getting a sum of 13 or more.

Solution:

If two dice are rolled together, then the total number of possible outcomes is 36 and list of total possible outcomes is

S = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

Sum of 11 in these outcomes = {(5,6),(6,5),(6,6)} = 3

The probability of getting a sum of 11 in these outcomes is

$P(\text{sum=11})=\dfrac{3}{36}$

$P(\text{sum=11})=\dfrac{1}{12}$

Therefore, the probability of getting a sum of 11 in these outcomes is $\dfrac{1}{12}$ .

Sum less than or equal to 4 = {(1,1),(1,2),(1,3),(2,1),(2,2),(3,1)} = 6

The probability of getting a sum less than or equal to 4 is

$P({sum\leq 4})=\dfrac{6}{36}$

$P({sum\leq 4})=\dfrac{1}{6}$

Therefore, the probability of getting a sum less than or equal to 4 is $\dfrac{1}{6}$ .

Sum of 13 or more = empty set because maximum sum is 12.

The probability of getting a sum of 13 or more is

$P(sum\geq 13)=\dfrac{0}{36}$

$P({sum\geq 13})=0$

Therefore, the probability of getting a sum of 13 or more is 0.

8 0

3 years ago

At a high school 7 student volunteer for a committtee how many different 5 person committees can be chosen

ki77a [65]

Total number of volunteer students for a committee = 7
Number of committee = 5

Number of ways of selecting the committee from the 7 volunteers = 7C5 = 7!/(5!*2!) = 21 ways.

There are 21 ways in which the 5-committee member can be selected from the 7 volunteers.

5 0

3 years ago

Write an expression that is equivalent to three over four (5z+ 16).

sattari [20]

Your answer is 15 over four z + 12. Using the distributive property, 3/4 • 5z equals 15/4z, which can't be simplified. Then 3/4 of 16 is 12. If you divide 16 by 4 (the denominator) and then multiply by 3 (the numerator) that yields your answer.

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3 years ago

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