Answer:
Please check the explanation.
Step-by-step explanation:
Given
f(x) = 3x + x³
Taking differentiate



solving






now solving




Thus, the expression becomes


Thus,
f'(x) = 3 + 3x²
Given that f'(x) = 15
substituting the value f'(x) = 15 in f'(x) = 3 + 3x²
f'(x) = 3 + 3x²
15 = 3 + 3x²
switch sides
3 + 3x² = 15
3x² = 15-3
3x² = 12
Divide both sides by 3
x² = 4



Thus, the value of x will be:

Hello,
f(x)=6x^3+18x²+12x=6x(x²+3x+2)
=6x(x²+x+2x+2)=6x((x(x+1)+2(x+1))
=6x(x+1)(x+2)
Zeros are 0,-1,-2
Answer:
The one you are or were about to pick is correct.
Step-by-step explanation:
Answer:
785
Step-by-step explanation:
Please don't spam :)
Hope this helps!