Answer:
The expectation the instructor to send each day
E(X) = 3.65
Step-by-step explanation:
Given data x : 0 1 2 3 4 5
P(X=x) : 0.05 0.05 0.1 0.1 0.4 0.3
The given data satisfy the two conditions
I) Given all probabilities are p₁(x) ≥0
ii) sum of all probabilities is equal to one
0.05 + 0.05 + 0.1 + 0.1 + 0.4 +0.3 =1
Therefore given data is discrete probability distribution
<u>Expectation</u> :-
suppose a random variable X assumes the values with respective probabilities , then the Expectation or Expected value of X , denoted by E(X) = ∑pi xi
on simplification, we get
E(X) = 3.65
TOMMY INITT TOMMY TOMMY TOMMY TOMMY PFP TOMMY PFP TOMMY PFP
Multiply the number of gallons per second by the number of seconds. <span>159*3= 477 </span>
<span>159*5= 795 </span>
<span>159*10= 1,590 </span>
3/4 = x / 36....3 purple to 4 yellow = x purple to 36 yellow
cross multiply
4x = 108
x = 108/4
x = 27....there are 27 purple marbles